Question

我试图将视图控制器显示为弹出窗口，当iPhone全屏显示时，它可以在iPhone上正常工作，但在iPad上崩溃。

@IBAction func selectOpponentItems(_ sender: UIButton) {

    let VC = storyboard?.instantiateViewController(withIdentifier: "ItemSelectionVC") as! ItemSelectionVC
    // Error here
    VC.delegate = self
    VC.preferredContentSize = CGSize(width: UIScreen.main.bounds.width / 2, height: UIScreen.main.bounds.height / 2)
    VC.modalPresentationStyle = UIModalPresentationStyle.popover
    self.present(VC, animated: true, completion: nil)
}

func adaptivePresentationStyle(for controller: UIPresentationController) -> UIModalPresentationStyle {
    return .none
}

错误消息显示：

无法转换类型的值＆＃39;的UIViewController＆＃39; （0x1b1e33f60）到＆＃39; Overpower.ItemSelectionVC＆＃39; （0x10005ad40）。

Answer 1

按照@TonyMkenu的回答，我将这两行代码添加到selectOpponentItems，它就像魔术一样：

VC.popoverPresentationController?.sourceView = sender
VC.popoverPresentationController?.sourceRect = sender.bounds

Popover视图控制器在iPad上崩溃

1 个答案: