基于具有多个返回值的子选择的MySQL删除语句。
以下是我现在正在做的事情:
DELETE FROM `dnsstats` WHERE id NOT IN
(
SELECT id FROM
(
SELECT id FROM `dnsstats` WHERE peerhost = 'x.x.x.243' ORDER BY id DESC LIMIT 500
) foo
)
AND id NOT IN
(
SELECT id FROM
(
SELECT id FROM `dnsstats` WHERE peerhost = 'x.x.x.40' ORDER BY id DESC LIMIT 500
) foo2
)
AND id NOT IN
(
SELECT id FROM
(
SELECT id FROM `dnsstats` WHERE peerhost = 'x.x.x.50' ORDER BY id DESC LIMIT 500
) foo3
);
这很好用,但我想动态选择各个IP地址:
SELECT peerhost FROM `dnsstats` GROUP BY peerhost;
..并根据返回的值删除。
这是我从上一个问题得到的:
DELETE FROM `dnsstats` WHERE id NOT IN
(
SELECT id FROM
(
SELECT id FROM `dnsstats` WHERE peerhost in (
SELECT peerhost FROM `dnsstats` GROUP BY peerhost
) ORDER BY id DESC LIMIT 500
) foo
);
..但这给我留下了500条记录。我想保留每个peerhost
知道我能做些什么来使这项工作?谢谢!
原始问题:MySQL delete statement based on sub-select with multiple return values
答案 0 :(得分:1)
我会使用变量来做到这一点。以下列举了每个peerhost
:
select s.*,
(@rn := if(@ph = peerhost, @rn + 1,
if(@ph := peerhost, 1, 1)
)
) as rn
from dnstats s cross join
(select @ph := '', @rn := 0) params
order by peerhost, id desc;
您可以使用子查询在delete
中使用它:
delete s
from dnstats s join
(select s.*,
(@rn := if(@ph = peerhost, @rn + 1,
if(@ph := peerhost, 1, 1)
)
) as rn
from dnstats s cross join
(select @ph := '', @rn := 0) params
order by peerhost, id desc
) es
on es.id = s.id
where rn > 500;
这会删除每个peerhost
的前500行以外的所有行。