我需要在Python中创建一个分散矩阵。我尝试使用scatter_matrix,但我想只留下对角线上方的散点图。
我正处于真正的开始阶段(没有走远),当列有名称(而不是默认数字)时,我遇到了麻烦。
这是我的代码:
import itertools
import numpy as np
import matplotlib.pyplot as plt
import pandas as pd
data=pd.DataFrame(np.random.randint(0,100,size=(10, 5)), columns=list('ABCDE')) #THE PROBLEM IS HERE - I WILL HAVE COLUMNS WITH NAMES
d = data.shape[1]
fig, axes = plt.subplots(nrows=d, ncols=d, sharex=True, sharey=True)
for i in range(d):
for j in range(d):
ax = axes[i,j]
if i == j:
ax.text(0.5, 0.5, "Diagonal", transform=ax.transAxes,
horizontalalignment='center', verticalalignment='center',
fontsize=16)
else:
ax.scatter(data[j], data[i], s=10)
答案 0 :(得分:1)
从数据框中选择列时出现问题。您可以使用Dim attachmentCount as integer
Dim saveFolder As String
saveFolder = "E:\Projects\Takeda\Data\Zipped Incremental data\incremental\"
attachmentCounter = itm.Attachments.count
For i = attachmentCounter to 1 Step -1
itm.Attachments(i).SaveAsFile saveFolder & "\" & itm.Attachments(i).DisplayName
Next
根据整数位置选择列。将您的最后一行更改为:
iloc
给出: