制作自定义名称生成器?

时间:2016-09-24 22:40:11

标签: java

为了编写家庭作业,我被要求为电视节目Babylon 5制作一个名称生成器。该节目应该包含你的名字,姓氏,最喜欢的城市和一个好朋友的名字。

  

名字:最喜欢的城市的最后3个字母+第一个的前3个字母   名称

     

姓氏:朋友姓名的最后3个字母+最后4个字母   名称

然后程序应该在每个名字的第一个辅音之前插入一个撇号(名称开头的辅音除外,在这种情况下,使用第二个辅音)。

除了撇号插入外,我已经完成了所有工作。

public class MMStarWarsNG {

    /**
     * @param c
     * @return
     */
    public static void main(String[] args) {
        // TODO code application logic here
        Scanner sc = new Scanner(System.in); //creates the scanner that allows user input

        System.out.print("What is your first name? ");
        String firstName = sc.nextLine(); //creates new line after user hits enter
        firstName = firstName.substring(0, 3); //locates the first three characters the the user typed. In this case the character are 0,1,2.

        System.out.print("What is your last name? ");
        String lastName = sc.nextLine();
        lastName = lastName.substring(0, 4); //takes the first 4 characters the the user typed, characters: 0,1,2,3

        System.out.print("What is your favorite city? ");
        String favCity = sc.nextLine();
        favCity = favCity.substring(favCity.length() - 3); //takes the final 3 characters that the user typed
        favCity = favCity.substring(0, 1).toUpperCase() + favCity.substring(1); //takes the first character typed and capatilizes it

        System.out.print("What is the first name of a good friend? ");
        String friend = sc.nextLine();
        friend = friend.substring(friend.length() - 3);
        friend = friend.substring(0, 1).toUpperCase() + friend.substring(1);

        String SWName = favCity + firstName + " " + friend + lastName;//adds all of the substrings together. The space after firstName is the space between the first and last name

        System.out.println(SWName); //prints the line above
    }

    public static boolean consonantFinder(char c) {

        String vowels = "euioa";

        for (int i = 0; i < vowels.length(); i++) {

            if (c == vowels.charAt(i)) {
                return false;
            }
        }
        return true;
    }

    public static int apostropheAdder(StringBuilder s) {
        //adds apostrophe
        int position;
        for (position = 0; position < s.length(); position++) { //linear search for the length of the string
            if (consonantFinder(s.charAt(position))) { //finds position
                if (position != 0) { //checks if position is the first letter
                    consonantFinder((char) position); //does consonantFinder on the position
                    if (consonantFinder((char) position) == true) { //adds apostrophe
                        s.insert(position, "'");
                        position++; //because of the randomness in my code, I've made it so that
                        //it can have more than one apostrophe
                    }

                }

            }
        }
        return position;
    }

}

2 个答案:

答案 0 :(得分:2)

首先,当辅音找到时,consonantFinder返回false会让人感到困惑,所以交换返回值。

然后,apostropheAdder可以使用spaceOccured标志修复:

public static int apostropheAdder(StringBuilder s) {
    int position;
    boolean spaceOccured = true;
    int lastSpacePosition = 0;
    for (position = 0; position < s.length(); position++) {
        if (s.charAt(position) == ' ') {
            spaceOccured = true;
            lastSpacePosition = position;
        }
        if (!spaceOccured) {
            continue;
        }
        if (consonantFinder(s.charAt(position))) {
            if (position == lastSpacePosition) {
                continue;
            }
            spaceOccured = false;
            s.insert(position, "'");
        }
    }
    return position;
}

答案 1 :(得分:1)

您的main不会调用方法apostropheAdder()。这是一个好的开始。添加该方法......或者查看我提供的内容。

    import java.util.*;
public class MMStarWarsNG {

    /**
     * @param c
     * @return
     */
    public static void main(String[] args) {
        // TODO code application logic here
        Scanner sc = new Scanner(System.in); //creates the scanner that allows user input

        System.out.print("What is your first name? ");
        String firstName = sc.nextLine(); //creates new line after user hits enter
        firstName = firstName.substring(0, 3); //locates the first three characters the the user typed. In this case the character are 0,1,2.

        System.out.print("What is your last name? ");
        String lastName = sc.nextLine();
        lastName = lastName.substring(0, 4); //takes the first 4 characters the the user typed, characters: 0,1,2,3

        System.out.print("What is your favorite city? ");
        String favCity = sc.nextLine();
        favCity = favCity.substring(favCity.length() - 3); //takes the final 3 characters that the user typed
        favCity = favCity.substring(0, 1).toUpperCase() + favCity.substring(1); //takes the first character typed and capatilizes it

        System.out.print("What is the first name of a good friend? ");
        String friend = sc.nextLine();
        friend = friend.substring(friend.length() - 3);
        friend = friend.substring(0, 1).toUpperCase() + friend.substring(1);

        String SWName = favCity + firstName + " " + friend + lastName;//adds all of the substrings together. The space after firstName is the space between the first and last name

        StringBuilder SWNameWapos = apostropheAdder(SWName);

        System.out.println(SWNameWapos); //prints the line above
    }

    public static boolean consonantFinder(char c) {

        String vowels = "euioa ";

        for (int i = 0; i < vowels.length(); i++) {

            if (c == vowels.charAt(i)) {
                return false;
            }
        }
        return true;
    }

    public static StringBuilder apostropheAdder(String a) {
        StringBuilder s = new StringBuilder(a);
        //adds apostrophe
        int position;
        for (position = 1; position < s.length(); position++) { //linear search for the length of the string
            if (consonantFinder(s.charAt(position))) { //finds position
                s.insert(position, "'");
                position++;
            }
        }
        return s;
    }
}