Question

我正在尝试为语句创建一个多项来测试数组的两个值。我有一个NSDate类型的数组，从核心数据中保存了多个日期。我的目标是从数组中获取日期，如果日期是在一个独特的日子，则将它们添加到新数组中。我想检查数组中的项目，如果它们具有相同的日期，则不将它们添加到新数组中。

目前我一直在使用calendar.components.Day来检查两个日期是否具有相同的值，但它没有返回正确的答案：

func consecutiveDatesCheck(dateArray: [NSDate]) -> Int {

    // The incoming parameter dateArray is immutable, so first make it mutable
    var mutableArray = dateArray

    // Next, sort the incoming array
    mutableArray.sortInPlace({ $0.compare($1) == NSComparisonResult.OrderedAscending })

    var x = 0
    var numberOfConsecutiveDays = 1
    var streakArray = [Int]()
    var notSameDays = [NSDate]()

    // Cycle through the array, comparing the x and x + 1 elements
    while x + 1 < mutableArray.count {

        let calendar: NSCalendar = NSCalendar.currentCalendar()
        let components = calendar.components(.Day, fromDate: mutableArray[x], toDate: mutableArray[x + 1], options: [])

        // If the difference between the dates is greater than 1, append the streak to streakArray and reset the counter
        if abs(components.day) = 0 {
            streakArray.append(numberOfConsecutiveDays)
            numberOfConsecutiveDays = 1
        }

            // If the difference between the days is exactly 1, add one to the current streak
        else if abs(components.day) == 1 {
            numberOfConsecutiveDays += 1
        }

        x += 1
    }

    // Append the final streak to streakArray
    streakArray.append(numberOfConsecutiveDays)
    print(streakArray)

    // Return the user's longest streak
    return streakArray.maxElement()!
}    /*

我在dateArray中的当前数据：

2016-08-20 06:38:23 +0000
2016-08-20 06:43:59 +0000
2016-08-20 06:49:19 +0000
2016-08-20 06:58:59 +0000
2016-08-20 07:05:44 +0000
2016-08-20 09:05:25 +0000
2016-09-02 12:05:55 +0000
2016-09-02 17:39:01 +0000
2016-09-03 13:37:31 +0000
2016-09-03 13:41:10 +0000
2016-09-03 13:59:36 +0000
2016-09-03 14:26:11 +0000
2016-09-03 14:48:57 +0000
2016-09-03 14:51:25 +0000
2016-09-03 15:06:56 +0000
2016-09-03 15:15:00 +0000
2016-09-04 13:53:48 +0000
2016-09-04 13:56:13 +0000
2016-09-04 14:16:29 +0000
2016-09-04 17:33:16 +0000
2016-09-05 16:53:32 +0000
2016-09-06 12:20:16 +0000
2016-09-06 15:19:14 +0000
2016-09-06 15:27:07 +0000
2016-09-06 15:30:48 +0000
2016-09-06 15:32:14 +0000
2016-09-06 15:39:34 +0000
2016-09-06 15:53:15 +0000
2016-09-06 16:08:45 +0000
2016-09-06 16:21:15 +0000
2016-09-06 17:41:09 +0000
2016-09-10 13:04:11 +0000

Answer 1

编辑：我不是100％明确您的要求。我想你想要的是你有测量数据的当天结束的连续天数。更新了我的答案。

func consecutiveDatesCheck(dateArray: [NSDate]) -> Int {
    let calendar = NSCalendar.currentCalendar()
    let uniqueDates = NSSet(array: dateArray.map { calendar.startOfDayForDate($0) }).sort {
        $0.timeIntervalSince1970 > $1.timeIntervalSince1970
    } as! [NSDate]

    var lastDate = calendar.startOfDayForDate(NSDate())
    var i = 0

    while i < uniqueDates.count && uniqueDates[i].compare(lastDate) == .OrderedSame {
        lastDate = calendar.dateByAddingUnit(.Day, value: -1, toDate: lastDate, options: [])!
        i += 1
    }

    return i
}

Swift：多项for循环检查数组中的输入值

1 个答案: