我正在尝试解析HTML文件,如下所示
var myArray = (byte[]) new ImageConverter().ConvertTo(InputImg, typeof(byte[]));
我尝试使用以下代码解析
<ol>
<li>
<div class="c1">
<span class="s1">hi</span>
" hello "
<span class="s2">world!</span>
</div>
</li>
<li>
<div class="c2">
<span class="s3">abc</span>
" def ghijkl "
<span class="s1">mno</span>
" pqr!"
</div>
</li>
</ol>
我得到了结果
tree = html.fromstring(code.content)
sol = tree.xpath('//ol//text()')
for x in sol:
print x
如何才能将每个hi
hello
world!
abc
def ghijkl
mno
pqr!
标记中的所有文字放在一行中。即我想要输出
<li>
答案 0 :(得分:1)
$ cat a.py
from lxml import etree
xml = """<ol>
<li>
<div class="c1">
<span class="s1">hi</span>
" hello "
<span class="s2">world!</span>
</div>
</li>
<li>
<div class="c2">
<span class="s3">abc</span>
" def ghijkl "
<span class="s1">mno</span>
" pqr!"
</div>
</li>
</ol>"""
tree = etree.fromstring(xml)
sol = tree.xpath('//ol//li')
for a in sol:
print " ".join([t.strip() for t in a.itertext()]).strip()
$ python a.py
hi " hello " world!
abc " def ghijkl " mno " pqr!"
答案 1 :(得分:1)
您可以获取每个li并使用normalize-space:
from lxml import html
h = """<ol>
<li>
<div class="c1">
<span class="s1">hi</span>
" hello "
<span class="s2">world!</span>
</div>
</li>
<li>
<div class="c2">
<span class="s3">abc</span>
" def ghijkl "
<span class="s1">mno</span>
" pqr!"
</div>
</li>
</ol>"""
tree = html.fromstring(h)
for li in tree.xpath("//ol/li"):
print(li.xpath("normalize-space(.)"))
这给了你:
hi " hello " world!
abc " def ghijkl " mno " pqr!"