Question

我尝试根据获取的信息创建动态查询。

当$ query2为例时：＆＃39;键入＆＃39; =＆GT; ＆＃39; PvP＆＃39;，＆＃39;在线＆＃39; =＆GT; ＆＃39;高级＆＃39;

$ query是：SELECT * FROM dispserveur WHERE type =：type AND online =：online

这很有效，

$req = $bdd->prepare("$query");
$req->execute(array('type' => 'PvP', 'online' => 'Premium'));

但是当我在执行中使用$ query2变量时，它无效。

$req = $bdd->prepare("$query"); //C
$req->execute(array($query2));

我每次都会得到同样的错误。

Warning: PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens

这是代码，

unset($sql);
unset($sql2);

if (isset($type2) AND $type2 != "all") {
$sql[] = " type = :type ";
$sql2[] = " 'type' => '$type2'";

}

if (isset($online2) AND $online2 != "all") {
$sql[] = " online = :online ";
$sql2[] = " 'online' => '$online2'";

}
if (isset($version2) AND $version2 != "all") {
$sql[] = " version LIKE :version ";
$sql2[] = " 'version' => %$version2%";

}

$query = "SELECT * FROM dispserveur";

if (!empty($sql)) {
$query .= ' WHERE ' . implode(' AND ', $sql);
}
if (!empty($sql2)) {
$query2 = implode(', ', $sql2); 
}

echo $query;
echo "<br />";
echo $query2;

$req = $bdd->prepare("$query"); //C
$req->execute(array($query2));
while ($red = $req->fetch())
{echo "$red[ip]<br />";}

感谢您的帮助！

Answer 1

// Swift 3 class AdaptiveSplitViewController : UISplitViewController { override func viewDidLoad() { super.viewDidLoad() evaulateOverlayType(for: self.traitCollection) } override func willTransition(to newCollection: UITraitCollection, with coordinator: UIViewControllerTransitionCoordinator) { super.willTransition(to: newCollection, with: coordinator) evaulateOverlayType(for: newCollection) } private func evaulateOverlayType(for traits: UITraitCollection) { if traits.horizontalSizeClass == .regular { self.preferredDisplayMode = .primaryOverlay } else { self.preferredDisplayMode = .automatic } } }的参数应该是一个关联数组，其键与execute()匹配。相反，您使用的是:paramName，它只是一个字符串。这就是你的代码无效的原因。

变化：

$query2

为：

$sql2[] = " 'type' => '$type2'";
$sql2[] = " 'online' => '$online2'";
$sql2[] = " 'version' => %$version2%";

之后，改变

$sql2['type']=$type2;
$sql2['online']=>$online2;
$sql2['version']=>"%$version2%";

到

$req->execute(array($query2));

动态sql查询 - 绑定变量数与令牌数不匹配

1 个答案: