Question

我有一个像这样的字符串

4741:GREEN,CIRHOSIS,ORANGE,Long-term,GREEN,HIS B CHIC,4642:GREEN,CRHOSIS,GREEN,HSysk B CC,

sting包含两个记录ID为4741和4642的记录。同样在记录中，其他所有内容都以逗号（，）

分隔

我怎么能分开这个刺痛。请注意，此示例字符串仅包含2条记录，但其他记录可能包含更多或更少或没有。谢谢你的帮助！

Answer 1

基本理念：

var str = "4741:GREEN,CIRHOSIS,ORANGE,Long-term,GREEN,HIS B CHIC,4642:GREEN,CRHOSIS,GREEN,HSysk B CC,1111:asdf"

var re = /(\d+):([^(\d+:)]+)/g;

var matches = str.match(re);

for(var x in matches){
    var parts = matches[x].split(":");
    var id = parts[0];
    var vals = parts[1].split(",");
    alert(id + "\n" + vals.length);
}

Answer 2

使用此：

var source = "4741:GREEN,CIRHOSIS,ORANGE,Long-term,GREEN,HIS B CHIC,4642:GREEN,CRHOSIS,GREEN,HSysk B CC,4643:GREEN,CRHOSIS,GREEN,HSysk B CC,4644:GREEN,CRHOSIS,GREEN,HSysk B CC,4645:GREEN,CRHOSIS,GREEN,HSysk B CC,4646:GREEN,CRHOSIS,GREEN,HSysk B CC,";

var extractRecordsAsArray = function (source) {
  var records = [];

  if (source && source.split) { // is string
    var re      = new RegExp("[0-9]+:[^0-9:]+", "g");
    var entries = source.match(re);

    for (var i = 0, len = entries.length; i < len; i++) {
      var entry = entries[i].split(':');

      records.push([entry[0], entry[1].split(',')]);
    }
  }
  return (records);
};

console.log("records: %o", extractRecordsAsArray(source));

或者，如果您更喜欢存储地图：

var extractRecordsAsMap = function (source) {
  var records = {};

  if (source && source.split) { // is string
    var re      = new RegExp("[0-9]+:[^0-9:]+", "g");
    var entries = source.match(re);

    for (var i = 0, len = entries.length; i < len; i++) {
      var entry = entries[i].split(':');

      records[entry[0]] = entry[1].split(',');
    }
  }
  return (records);
};

console.log("records: %o", extractRecordsAsMap(source));

不保证防弹并且效率最高，但是对于相当大的字符串会获得不错的性能并且工作正常。

Answer 3

function split(str) {
  var split = str.split(/,?(\w+):/);
  var result = {};
  for (var i = 1; i < split.length; i+=2) {
     result[split[i]] = split[i+1].split(/,/);
  }  
  return result;
}
split("4741:GREEN,CIRHOSIS,ORANGE,Long-term,GREEN,HIS B CHIC,4642:GREEN,CRHOSIS,GREEN,HSysk B CC"); 
// => {'4642': ['GREEN', 'CRHOSIS', 'GREEN', 'HSysk B CC'], '4741': ['GREEN', 'CIRHOSIS', 'ORANGE', 'Long-term', 'GREEN', 'HIS B CHIC']}

Answer 4

您可以使用String.match函数：

var records = "4741:GREEN,CIRHOSIS,ORANGE,Long-term,GREEN,HIS B CHIC,4642:GREEN,CRHOSIS,GREEN,HSysk B CC,"
var regex = /[0-9]+:([a-zA-Z0-9]*,)+/gi;
records.match(regex);

结果： ["4741:GREEN,CIRHOSIS,ORANGE,", "4642:GREEN,CRHOSIS,GREEN,"]

如果您正在寻找更具体的内容，则需要延长您的问题。

另一个有趣的事情可能是在字符串中添加大括号，括号和引号，然后是JSON.parse（）它。

在JS中掷出一个字符串

4 个答案: