Question

假设当我导航到上一页时我在recyclerview中选择了位置3并再来一次我想要选择recyclerview的第一项

    int selectposition = 0;


if (selectedPosition == position ) {
            chckbox.setVisibility(View.VISIBLE);
            chckbox.setChecked(true);
            chckbox.setBackgroundResource(R.drawable.checkbox_selector);
            chckbox.forceLayout();
            layout.setBackgroundResource(R.drawable.selected_address_bg);

        } else {
            chckbox.setVisibility(View.VISIBLE);
            chckbox.setChecked(false);
            layout.setBackgroundResource(R.color.white);
        }

Answer 1

在onBind方法中，选择第一个位置，以便每当您返回另一个活动并再次返回时，将选择第一个项目。

if(position == 0){
chckbox.setChecked(true);
chckbox.setBackgroundResource(R.drawable.checkbox_selector);
}

Answer 2

2天后，我得到了最终解决方案如下：

// Make your Adapter...
mLeftAdapter = new LeftMenuAdapter(mContext, mFilterValuesArray);

// Bind it to RecyclerView
mFilterBinding.filterLeftRecyclerView.setAdapter(mLeftAdapter);

//Call this method which will perform click for 0'th position after computing (binding) all data...
postAndNotifyAdapter(new Handler(), mFilterBinding.filterLeftRecyclerView);

postAndnotifyAdapter 方法将如下：

protected void postAndNotifyAdapter(final Handler handler, final RecyclerView recyclerView) {
    handler.post(new Runnable() {
        @Override
        public void run() {
            if (!recyclerView.isComputingLayout()) {
                // This will call first item by calling "performClick()" of view.
                ((LeftMenuAdapter.ViewHolder) recyclerView.findViewHolderForLayoutPosition(0)).mView.performClick();
            } else {
                postAndNotifyAdapter(handler, recyclerView, adapter);
            }
        }
    });
}

愿这对你有所帮助。：）

Answer 3

您可以通过以下代码滚动到第一个位置：您可以使用布局管理器替换

LinearLayoutManager layoutManager = (LinearLayoutManager) mRecyclerView
                    .getLayoutManager();
            layoutManager.scrollToPositionWithOffset(0, 0);

如何在recyclerview中选择第一项

3 个答案: