Question

我试图遍历所有玩家和

1＆GT;输出一行 2 - ;创建一个对象

基于某些条件。但是我收到了Stackoverflow错误。

public void refuteSuggestion(Weapon w, Character c, int currentPlayerNumber) {
    for (Player p : game.getPlayers()) {
        if(currentPlayerNumber != 6) {
            if (p.getNum() == currentPlayerNumber + 1) {
                Set<Card> cardSet = new HashSet<>();
                cardSet.addAll(p.getPlayerCards());
                Card card = (Card) getRandomObject(cardSet);
                System.out.println(card.getName(0));
            } else {
                refuteSuggestion(w, c, currentPlayerNumber + 1);
            }
        }
        else{
            refuteSuggestion(w, c, 0);
        }

    }
    System.out.println("No one refuted...");
}

Answer 1

不确定你在这里尝试做什么，但是你是在同一个方法中调用方法，这是一个无限循环。因此堆栈溢出错误。

在你的Else条件中，你只是改变currentPlayerNumber的值，所以只需这样做而不是在更改currentPlayerNumber之后调用相同的函数。

如果逻辑更容易理解，你也可以创建一个单独的函数来处理你的代码。

public void refuteSuggestion(Weapon w, Character c, int currentPlayerNumber) {
    for (Player p : game.getPlayers()) {
        if(currentPlayerNumber != 6) {
            if (p.getNum() == currentPlayerNumber + 1) {

                  nextFunction(p);
            } else {
                currentPlayerNumber += 1;
            }
        }
        else{
            currentPlayerNumber = 0;
        }

    }
    System.out.println("No one refuted...");
}

public void nextFunction(Player p){
    Set<Card> cardSet = new HashSet<>();
    cardSet.addAll(p.getPlayerCards());
    Card card = (Card) getRandomObject(cardSet);
    System.out.println(card.getName(0));
  }

循环时出现堆栈溢出错误

1 个答案: