Question

我有一串混合内容，如：

{json stuff}来自同一输出的其他内容有＆lt; html＆gt;标签喜欢＆LT; div＆gt; some＆lt; / div＆gt;还有更多东西，最后还有另外一个{json stuff}

所以我需要的是能够使用这3个元素：
所以为了得到第一个json，我这样做：

$first_json = json_decode(substr($mixed_string,0, strpos($mixed_string,"}")+1 ));
// that will get me the first json content
// Then I need the second json which is at the end of the string, 
// the length of the string is unknown , the json length is unknown
// after that I just do:
echo preg_replace("/\{[^)]+\}/","",$mixed_string);
// and I get the html from that string...

那么，我怎样才能得到最后一个json？

Answer 1

你可以使用正则表达式来获取JSON值，它可以让你从任何字符串中获取JSON，无论长度如何。假设您的{ "publishOptions": { "include": [ "wwwroot", "Views", "Areas/**/Views", "settings.json", "settings.production.json", "web.config" ] } }内容ID为div，div包含您要提取的JSON：

编辑：将提取过程添加为函数。

function extractJSON(content) {
  var regex = /({.*?})/g,
    raw = content.match(regex),
    output = [],
    errors = [];

  raw.forEach(function(el) {
    try {
      output.push(JSON.parse(el));
    } catch (e) {
      errors.push('issue with object: ' + el);
    }
  });

  return {
    results: output,
    errors: errors
  }
}

// Grab the elements that contain JSON
var elements = document.getElementById('content').innerHTML;

console.log(extractJSON(elements));

从混合内容字符串中提取json

1 个答案: