如何使用opencv在c ++中使用像素值执行算术运算？

Question

我有一组70个RGB图像（argc = 71）。我想根据这些公式更改像素值：

l1 =（R-G）^ 2 /（（R-G）^ 2 +（R-B）^ 2 +（G-B）^ 2）;

l2 =（R-B）^ 2 /（（R-G）^ 2 +（R-B）^ 2 +（G-B）^ 2）;

13 =（R-G）^ 2 /（（G-B）^ 2 +（R-B）^ 2 +（G-B）^ 2）;

然后存储新图像。我尝试使用c ++的代码如下，但我一直收到这个错误：

SetPixels（99556,0x7fff76450000）malloc：*对象0x10a9ce000的错误：未分配的指针*在malloc_error_break中设置断点以进行调试

任何人都可以帮我解决这个问题吗？

提前致谢！

#include <highgui.h>
#include <cv.h>
#include <sstream>
using namespace cv;
using namespace std;
int main(int agra, char** argv){
for(int k=1;k<=argc;k++){

        char* imageName = argv[k];
        Mat image;
        image = imread(imageName,CV_LOAD_IMAGE_UNCHANGED);

        uchar l1;
        uchar l2;
        uchar l3;

        for (int i=0; i<=image.rows;i++){
            for (int j=0; j<=image.cols; j++){
                Vec3b intensity = image.at<Vec3b>(Point(j, i));
                uchar red = intensity.val[0];
                int int_red = (int) red;
                uchar green = intensity.val[1];
                int int_green = (int) green;
                uchar blue = intensity.val[2];
                int int_blue = (int) blue;

                int int_l1 = pow((int_red-int_green),2)/(pow((int_red-int_green),2)+pow((int_red - int_blue),2)+pow((int_green-int_blue),2));
                int int_l2 = pow((int_red-int_blue),2)/(pow((int_red-int_green),2)+pow((int_red - int_blue),2)+pow((int_green-int_blue),2));
                int int_l3 = pow((int_green-int_blue),2)/(pow((int_red-int_green),2)+pow((int_red - int_blue),2)+pow((int_green-int_blue),2));

                l1 = (uchar) int_l1;
                l2 = (uchar) int_l2;
                l3 = (uchar) int_l3;

                intensity.val[0] = l1;
                intensity.val[1] = l2;
                intensity.val[2] = l3;

                image.at<Vec3b>(j,i)= intensity;

            }
        }

        stringstream ss;
        string name = "l1l2l3image_";
        string type = ".jpg";
        ss<<name<<(k)<<type;
        string filename = ss.str();
        ss.str("");
        imwrite(filename, image);
    }
    return 0;
    }