使用带有jquery选择器的变量

Question

我有以下代码行，我想使用visibleoffer变量作为选择器。我该如何连接它？

var visibleoffer = '.' + obj.parents('tbody').attr('providername') + ' .visible-offers'; //visibleoffer = .Txy .visible-offers
$(obj).parents('.Provider').find(".Offers:not(.HideByProviderFilter,.HideByMainFilter,.HideByProviderFilter.HideByMainFilter,+ visibleoffer)").length;

所以它变成了：

$(obj).parents('.Provider').find(".Offers:not(.HideByProviderFilter,.HideByMainFilter,.HideByProviderFilter.HideByMainFilter,.Txy .visible-offers)").length;

Answer 1

您需要在构建选择器字符串时连接变量：

$(obj).parents('.Provider').find(".Offers:not(.HideByProviderFilter,.HideByMainFilter,.HideByProviderFilter.HideByMainFilter," + visibleoffer +")").length;