Question

我有一个1000值的向量，然后我用100个箱子做一个直方图。我想创建一个vector =（Value，Freq），其值为单个值（因此我将有1000个），freq =特定值所在的bin中值的计数。

希望这可以使问题更清楚：

data <- c(6.429229, 9.300965, 11.073744, 6.527263, 8.425178, 
          6.821384, 6.515991,  9.131452, 6.313888, 8.866572) 
Myhist <- hist(data,2)
Myhist$counts
# 5 4 1

# c(5,4,1,5,4,5,5,4,5,4)
MyDF <- cbind(data,c(5,4,1,5,4,5,5,4,5,4))
# Result I want: 

# [1,]  6.429229 5
# [2,]  9.300965 4
# [3,] 11.073744 1
# [4,]  6.527263 5
# [5,]  8.425178 4
# [6,]  6.821384 5
# [7,]  6.515991 5
# [8,]  9.131452 4
# [9,]  6.313888 5
#[10,]  8.866572 4

Answer 1

根据你的例子，我猜你想要的是知道在直方图中落入同一个bin的值的数量（包括有问题的值）。您似乎也指定了直方图中断。

data <- c(6.429229, 9.300965, 11.073744, 6.527263, 8.425178, 
          6.821384, 6.515991,  9.131452, 6.313888, 8.866572)

get.num.in.bin <- function(data, hist.breaks=2){
  Myhist   <- hist(data, breaks=hist.breaks, plot=FALSE)
  cats     <- as.numeric(cut(data, breaks=Myhist$breaks, labels=1:3))
  counts   <- Myhist$counts[cats]
  new.data <- data.frame(data=data, num.in.bin=counts)
  return(new.data)
}
get.num.in.bin(data)
#         data num.in.bin
# 1   6.429229          5
# 2   9.300965          4
# 3  11.073744          1
# 4   6.527263          5
# 5   8.425178          4
# 6   6.821384          5
# 7   6.515991          5
# 8   9.131452          4
# 9   6.313888          5
# 10  8.866572          4

将单个值与每个直方图箱的计数组合

1 个答案: