Question

我有一个数组，我正在尝试使用脚本创建一个嵌套字典，该脚本将根据数组值自动更新字典

string[,] items = new string[8, 3] { 
    { "blue", "one","available" },
    { "blue", "two","available" },
    { "blue", "three","not available" },
    { "black", "six", "not available"},
    { "black", "four","available" },
    { "brown", "one","available" },
    { "brown", "seven","available" },
    { "brown", "six","not available" }
};

所以我期待像这样的输出

[{
    "blue": {
        "one": {
            "available": ["store1 ", "store2 "]
        },
        "two": {
            "available": ["store1 ", "store2 "]
        },
        "three": {
            "not available": ["store1 ", "store2 "]
        }

    }

}, {
    "black": {
        "three": {
            "not available": ["store1 ", "store2 "]
        },
        "six": {
            "available": ["store1 ", "store2 "]
        },
        "four": {
            "not available": ["store1 ", "store2 "]
        }
    }
}, {
    "brown": {
        "one": {
            "available": ["store1 ", "store2 "]
        },
        "seven": {
            "availble": ["store1 ", "store2 "]
        },
        "size": {
            "not available": ["store1 ", "store2 "]
        }

    }
}]

我是c＃的新手，如何以上述格式创建嵌套字典？

Answer 1

[store1,store2]作为每个元素的默认值：

Dictionary<string, Dictionary<string, Dictionary<string, List<string>>>> dictionaryLevel0 = new Dictionary<string, Dictionary<string, Dictionary<string, List<string>>>>();

string[,] items = new string[8, 3]
{
    {"blue", "one", "available"}, {"blue", "two", "available"},
    {"blue", "three", "not available"}, {"black", "six", "not available"}, {"black", "four", "available"}, {"brown", "one", "available"}, {"brown", "seven", "available"},
    {"brown", "six", "not available"}
};

for (int i = 0; i <= items.GetUpperBound(0); i++)
{
    if(!dictionaryLevel0.ContainsKey(items[i, 0]))
        dictionaryLevel0.Add(items[i, 0], new Dictionary<string, Dictionary<string, List<string>>>());

    var dictionaryLevel1 = dictionaryLevel0[items[i, 0]];

    if (!dictionaryLevel1.ContainsKey(items[i, 1]))
        dictionaryLevel1.Add(items[i, 1], new Dictionary<string, List<string>>());

    var dictionaryLevel2 = dictionaryLevel1[items[i, 1]];

    if (!dictionaryLevel2.ContainsKey(items[i, 2]))
        dictionaryLevel2.Add(items[i, 2], new List<string> { "store1", "store2"});
}

在c＃中自动从值创建嵌套字典

1 个答案: