Question

尽管在urls.py中包含了url名称，但我收到了以下错误：

Reverse for 'upload' with arguments '()' and keyword arguments '{}' not found.0 pattern(s) tried: []

我已将网址名称设为＆＃39;上传＆＃39;在urls.py中最初home.html应该发布到＆＃39;上传＆＃39;这是我包含的FileView：

url(r'^upload/',FileView.as_view(),name='upload')

views.py

def initial(request):
    return render(request,'display/home.html')

class FileView(FormView):
    template_name = 'display/upload.html'
    form_class = FileForm
    success_url = 'success/'


    def form_valid(self, form):
    file_upload = FileModel(
    fileup=self.get_form_kwargs().get('files')['fileup'])

    #results = FileForm.objects.filter(Q(name__icontains=your_search_query)     | Q(startdate__icontains=your_search_query) |   Q(enddate__icontains=your_search_query)).order_by('pub_date')

     file_upload.save()
    self.id = file_upload.id
    return render_to_response('display/success.html')
    return HttpResponseRedirect(self.get_success_url())

    def get_success_url(self):
    return reverse('file_upload', kwargs={'pk': self.id})

def redirect(request):
    return render(request,"display/success.html")
...

urls.py

from django.conf.urls import url

from . import views

from display.views import FileView

urlpatterns = [
    url(r'^start/', views.initial,name='home'),
    url(r'^upload/',FileView.as_view(),name='upload'),
    url(r'^success/',views.redirect,name='success'),
    #url(r'^upload',views.upload,name='upload'),
    ]

模板 home.html的

<!DOCTYPE html>
<html>
    <head>
        <title>CSV FILE UPLOAD</title>
    </head>

<body>
    <form enctype="multipart/form-data" method="POST" action="{% url 'upload' %}">
        {% csrf_token %}



        <input type="submit" name="submit"  />
    </form>
</body>

Answer 1

这个urls.py看起来不像根网址...可能是根网址内的包含内容丢失了吗？

示例：

urlpatterns = [
    url(r'^display/', include('display.urls', namespace='display')),
]

如果包含这样的内容，您应该将upload网址称为：

<form enctype="multipart/form-data" method="POST" action="{% url 'display:upload' %}">

其他可能的解决方案，请尝试在网址正则表达式的末尾添加$：

from django.conf.urls import url

from . import views

from display.views import FileView

urlpatterns = [
    url(r'^start/$', views.initial,name='home'),
    url(r'^upload/$',FileView.as_view(),name='upload'),
    url(r'^success/$',views.redirect,name='success'),
]

我收到错误NoReverseMatch，尽管在urls.py

1 个答案: