Question

我有一种情况需要从我们的MEMBERS表中为特定网站选择潜在客户（＆＃39; P＆＃39;的关系）。但是，当我选择这些人时，我需要排除这两个潜在客户的两组。这些组中的每一个都在名为MEMBERUDFS的单独表中具有条目。现在，MEMBERS表中的所有条目都不会在MEMBERUDFS表中有一个条目。因此，我尝试使用两个＆＃34; NOT IN＆＃34;从主查询中排除这些组。子查询，但似乎不起作用。我可以使用以下查询来隔离排除组：

SELECT  MEMBERS_1.memid
FROM MEMBERS AS MEMBERS_1
JOIN SITES AS SITES_1 ON MEMBERS_1.siteid = SITES_1.siteid
LEFT JOIN MEMBERUDFS AS MEMBERUDFS_1 ON MEMBERS_1.memid = MEMBERUDFS_1.memid
JOIN MEMBERUDFSETUPS AS MEMBERUDFSETUPS_1 ON MEMBERUDFS_1.udfid = MEMBERUDFSETUPS_1.udfid
WHERE (MEMBERS_1.relationship = 'P')
    AND (MEMBERS_1.email <> '')
    AND (MEMBERUDFS_1.udfid = '26')
    AND (MEMBERUDFS_1.udfvalue = 'No')
    AND (MEMBERS_1.entrydate < DATEADD(DAY, -6, GETDATE()))
    AND (MEMBERS_1.siteid = @rvSite)

这个查询：

SELECT  MEMBERS_2.memid
FROM MEMBERS AS MEMBERS_2
JOIN SITES AS SITES_2 ON MEMBERS_2.siteid = SITES_2.siteid
LEFT JOIN MEMBERUDFS AS MEMBERUDFS_2 ON MEMBERS_2.memid = MEMBERUDFS_2.memid
JOIN MEMBERUDFSETUPS AS MEMBERUDFSETUPS_2 ON MEMBERUDFS_2.udfid = MEMBERUDFSETUPS_2.udfid
WHERE (MEMBERS_2.relationship = 'P')
    AND (MEMBERS_2.email <> '')
    AND (MEMBERUDFS_2.udfid = '25')
    AND (MEMBERUDFS_2.udfvalue = 'Yes')
    AND (MEMBERS_2.entrydate < DATEADD(DAY, -21, GETDATE()))
    AND (MEMBERS_2.siteid = @rvSite)

所以这就是我一直放在一起的东西，但它并没有消除这两个分组：

SELECT  MEMBERS.scancode,
        MEMBERS.memid,
        MEMBERS.fname,
        MEMBERS.lname,
        MEMBERS.relationship,
        MEMBERS.status,
        MEMBERS.email,
        MEMBERS.entrydate,
        SITES.sitename
FROM MEMBERS
JOIN SITES ON MEMBERS.siteid = SITES.siteid
WHERE (MEMBERS.relationship = 'P')
    AND (MEMBERS.email <> '')
    AND (MEMBERS.siteid = @rvSite)
    AND (MEMBERS.memid NOT IN (
        SELECT MEMBERS_1.memid
        FROM MEMBERS AS MEMBERS_1
        JOIN SITES AS SITES_1 ON MEMBERS_1.siteid = SITES_1.siteid
        LEFT JOIN MEMBERUDFS AS MEMBERUDFS_1 ON MEMBERS_1.memid = MEMBERUDFS_1.memid
        JOIN MEMBERUDFSETUPS AS MEMBERUDFSETUPS_1 ON MEMBERUDFS_1.udfid = MEMBERUDFSETUPS_1.udfid
        WHERE (MEMBERS_1.relationship = 'P')
            AND (MEMBERS_1.email <> '')
            AND (MEMBERUDFS_1.udfid = '26')
            AND (MEMBERUDFS_1.udfvalue = 'No')
            AND (MEMBERS_1.entrydate < DATEADD(DAY, -6, GETDATE()))
            AND (MEMBERS_1.siteid = @rvSite))
    )
    AND (MEMBERS.memid NOT IN (
        SELECT MEMBERS_2.memid
        FROM MEMBERS AS MEMBERS_2
        JOIN SITES AS SITES_2 ON MEMBERS_2.siteid = SITES_2.siteid
        LEFT JOIN MEMBERUDFS AS MEMBERUDFS_2 ON MEMBERS_2.memid = MEMBERUDFS_2.memid
        JOIN MEMBERUDFSETUPS AS MEMBERUDFSETUPS_2 ON MEMBERUDFS_2.udfid = MEMBERUDFSETUPS_2.udfid
        WHERE (MEMBERS_2.relationship = 'P')
            AND (MEMBERS_2.email <> '')
            AND (MEMBERUDFS_2.udfid = '25')
            AND (MEMBERUDFS_2.udfvalue = 'Yes')
            AND (MEMBERS_2.entrydate < DATEADD(DAY, -21, GETDATE()))
            AND (MEMBERS_2.siteid = @rvSite))
    )

任何帮助将不胜感激

Answer 1

你只需要玩你的where子句......

 AND (MEMBERS.memid NOT IN (
    SELECT MEMBERS_1.memid
    FROM MEMBERS AS MEMBERS_1
    JOIN SITES AS SITES_1 ON MEMBERS_1.siteid = SITES_1.siteid
    LEFT JOIN MEMBERUDFS AS MEMBERUDFS_1 ON MEMBERS_1.memid = MEMBERUDFS_1.memid
    JOIN MEMBERUDFSETUPS AS MEMBERUDFSETUPS_1 ON MEMBERUDFS_1.udfid = MEMBERUDFSETUPS_1.udfid
    WHERE (MEMBERS_1.relationship = 'P')
        AND (MEMBERS_1.email <> '')
        AND (MEMBERS_1.siteid = @rvSite)
        AND (((MEMBERUDFS_1.udfid = '26') AND (MEMBERUDFS_1.udfvalue = 'No') AND (MEMBERS_1.entrydate < DATEADD(DAY, -6, GETDATE()))) OR
             ((MEMBERUDFS_1.udfid = '25') AND (MEMBERUDFS_1.udfvalue = 'Yes') AND (MEMBERS_1.entrydate < DATEADD(DAY, -21, GETDATE()))))

SQL Not In子查询

1 个答案: