Question

我在特定坐标（x，y，z）处通过脚本实例化对象，之后我想在特定坐标（x，y，z）处旋转它。这是我的代码，但它没有旋转

using UnityEngine;
using System.Collections;
public class Generator : MonoBehaviour {
public GameObject fire;
//public GameObject firetaps;
//System.Random randomize = new System.Random();
// Use this for initialization
void Start () {
    //int fun=randomize.Next(1,6);
    switch (1) {
    case 1:
        PlaceFire();
        break;
    /*case 2:
        PlaceFire1 ();
        break;
    case 3:
        PlaceFire2 ();
        break;*/
      }
     }
    void PlaceFire()
    {
    Instantiate(fire, GeneratedPosition(), Quaternion.identity);
fire.transform.eulerAngles = new Vector3         (275.0941f,287.0612f,72.63131f);// it does not rotate :-(
    //fire.transform.Rotate(275.0941f,287.0612f,72.63131f);
}
Vector3 GeneratedPosition()
{
    float x,y,z;
    x = -142.5f;
    y = 39.165f;
    z =9.9817f;
    return new Vector3(x,y,z);
}

Answer 1

您需要在火场中存储Instantiate的返回值。你永远不会旋转实例化的游戏对象。（也阅读编辑!!）

Instantiate(fire, GeneratedPosition(), Quaternion.identity);
fire.transform.eulerAngles = new Vector3(275.0941f,287.0612f,72.63131f);

应该是

fire = Instantiate(fire, GeneratedPosition(), Quaternion.identity) as GameObject;
fire.transform.eulerAngles = new Vector3(275.0941f,287.0612f,72.63131f);

你的魔法值也很奇怪。

修改我刚刚意识到火是你的预制件。所以你可能想要使用局部变量。

GameObject fireInstance = Instantiate(fire, GeneratedPosition(), Quaternion.identity) as GameObject; fireInstance.transform.eulerAngles = new Vector3(275.0941f,287.0612f,72.63131f);

Instantiate的这个重载的第三个参数已经进行了一次旋转，为什么不立即将它传递给那里呢？

Instantiate(fire, GeneratedPosition(), Qaternion.Euler(275.0941f,287.0612f,72.63131f));

如果您仍然需要参考，那么，取决于。但请注意它是如何仅返回您需要转换为所需类型的对象。

通过Instantiate对象上的脚本旋转对象

1 个答案: