Question

我想访问if语句之外的列表，python中是否有静态函数？

列表为switch1Flow，switch2Flow和switch3Flow：

这是代码

def startingNode(self, destID, message, counter):
    pack =  self.pac.packet(self.name, destID, message) 
    if counter == "0":
        nextHop = self.controller.selectSwitch(self.name)
        print "Switch", self.name, "contacts controller"
        nextHop.receivePacket(pack)
        switch1Flow = [nextHop.name] //list1
        print switch1Flow
        nextHop1 = self.controller.selectSwitch(nextHop.name)
        print "Switch", nextHop.name, "contacts controller"
        nextHop1.receivePacket(pack)
        nextHop2 = self.controller.selectSwitch(nextHop1.name)
        print "Switch",nextHop1.name,"contacts controller"
        nextHop2.receivePacket(pack)
        switch2Flow = [self.name, nextHop1.name] // list2
        print switch2Flow
        switch3Flow = [nextHop.name, nextHop2.name] // list3
        print switch3Flow
    elif counter == "1":
        if 's2' in switch1Flow:
           print "forwarding to s2"
           if 's1' in switch2Flow and 's3' in switch2Flow:
             print "forwarding to s3"
             if 's2' in switch3Flow and 's4' in switch3Flow:
                 print "forwarding to s4"
                 print "message reched s4"

我想访问switch1Flow，switch2Flow和switch3Flow以便在elif中访问。你能建议我怎么做？

Answer 1

定义clone条件之外的开关变量你应该没问题：

finalize

如何在if语句之外使列表可访问？

1 个答案: