这是我的问题:我可以在我的设备中获取已安装应用程序的列表,但我需要列表中只有确定应用程序的列表。我的意思是,例如,我只会在列表中显示我的应用程序..我该怎么办?我可以看一下包名吗?有没有其他方法可以过滤此列表以显示我想要的应用程序?这是我使用的代码:
适配器:
public class LocalAppListAdapter extends ArrayAdapter<ApplicationInfo> {
private List<ApplicationInfo> appsList = null;
private Context context;
private PackageManager packageManager;
public LocalAppListAdapter(Context context, int textViewResourceId, List<ApplicationInfo> appsList) {
super(context, textViewResourceId, appsList);
this.context = context;
this.appsList = appsList;
packageManager = context.getPackageManager();
}
@Override
public int getCount() {
return ((null != appsList) ? appsList.size() : 0);
}
@Override
public ApplicationInfo getItem(int position) {
return ((null != appsList) ? appsList.get(position) : null);
}
@Override
public long getItemId(int position) {
return position;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View view = convertView;
if (null == view) {
LayoutInflater layoutInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
view = layoutInflater.inflate(R.layout.local_app_list_row, null);
}
ApplicationInfo applicationInfo = appsList.get(position);
if (null != applicationInfo) {
TextView appName = (TextView) view.findViewById(R.id.app_name);
TextView packageName = (TextView) view.findViewById(R.id.app_paackage);
ImageView iconview = (ImageView) view.findViewById(R.id.app_icon);
appName.setText(applicationInfo.loadLabel(packageManager));
packageName.setText(applicationInfo.packageName);
iconview.setImageDrawable(applicationInfo.loadIcon(packageManager));
}
return view;
}
};
我用来获取列表的类:
public class LocalAppList extends AppCompatActivity {
private PackageManager packageManager = null;
private List<ApplicationInfo> applist = null;
private LocalAppListAdapter listadaptor = null;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.local_app_list);
packageManager = getPackageManager();
new LoadApplications().execute();
}
private List<ApplicationInfo> checkForLaunchIntent(List<ApplicationInfo> list) {
ArrayList<ApplicationInfo> applist = new ArrayList<ApplicationInfo>();
for (ApplicationInfo info : list) {
try {
if (null != packageManager.getLaunchIntentForPackage(info.packageName)) {
applist.add(info);
}
} catch (Exception e) {
e.printStackTrace();
}
}
return applist;
}
private class LoadApplications extends AsyncTask<Void, Void, Void> {
private ProgressDialog progress = null;
@Override
protected Void doInBackground(Void... params) {
applist = checkForLaunchIntent(packageManager.getInstalledApplications(PackageManager.GET_META_DATA));
listadaptor = new LocalAppListAdapter(LocalAppList.this, R.layout.local_app_list, applist);
return null;
}
@Override
protected void onCancelled() {
super.onCancelled();
}
@Override
protected void onPostExecute(Void result) {
ListView list = (ListView) findViewById(R.id.localAppList);
list.setAdapter(listadaptor);
progress.dismiss();
super.onPostExecute(result);
}
@Override
protected void onPreExecute() {
progress = ProgressDialog.show(LocalAppList.this, null, "Loading application info...");
super.onPreExecute();
}
@Override
protected void onProgressUpdate(Void... values) {
super.onProgressUpdate(values);
}
}
}
所以这实际上是包含所有应用程序的完整列表..我需要找到一种方法来过滤列表,例如只显示谷歌应用程序或我想要显示的列表。
答案 0 :(得分:0)
您可以使用此方法显示已安装应用程序的列表,其中筛选所有系统级应用程序,即无法启动的应用程序。
/**
* This method is used to fetch all the application installed in device.
* @param Context
* @return List<ApplicationInfo>
*/
public static List<ApplicationInfo> getInstalledApplication(Context c)
{
List<ApplicationInfo> installedApps = c.getPackageManager().getInstalledApplications(PackageManager.PERMISSION_GRANTED);
List<ApplicationInfo> launchableInstalledApps = new ArrayList<ApplicationInfo>();
for(int i =0; i<installedApps.size(); i++)
{
if(c.getPackageManager().getLaunchIntentForPackage(installedApps.get(i).packageName) != null)
{
//If you're here, then this is a launch-able app
launchableInstalledApps.add(installedApps.get(i));
}
}
return launchableInstalledApps;
}
我希望这会有所帮助。