Question

我有一个日期列表，想要从日期（8月1日SA）一直到下一个日期的开头捕获信息 EG（31 Jul FR 0135 HKG MEL 33K 18:00 19:44）在第一个实例中和（01 Aug SA 06:40 07:10 11:10）在下一个等等。

我所拥有的正则表达式是展望未来，但我不知道该怎么做。

regex:: $pattern = '/.*(?=\d{2}\s+[A-Z][a-z]{2}\s+\w{2})/';

31 Jul FR 0135 HKG MEL 33K 18:00 19:44 01 8月SA
  06:40 07:10 11:10 02 8月SU 0134 MEL HKG 33K 06:40 07:37   15:21 15:51 11:11 03 8月MO G 04 Aug TU 0905 HKG   MNL 330 20:50 22:52 05 Aug WE 00:58
  0912 MNL HKG 330 08:32 10:36 11:06 14:16 06 8月TH T2024
  P2 19:00 19:00 07 Aug FR 00:30 00:30 05:30
  T2314 2R 22:00 22:00 08 Aug SA 06:00 06:00   08:00 09 8月8月8日8月8日   TU R13 06:00 06:00 06:06 06:06 00:06 0699 HKG BOM
  33G 16:20 17:53 21:07 21:37 07:47 12月12日我们13   Aug TH RPT 00:00 00:00 02:45 02:45 02:45 14 August FR 0660   BOM HKG 33G 03:05 04:15 12:48 13:18 07:43 15 SA SA R13
  06:00 06:00 11:23 11:23 05:23 T1514 CW 14:00 14:00 19:30   19:30 05:30 16 8月SU 0494 HKG TPE 33G 10:30 12:16 14:08
  0495 TPE HKG 33G 14:59 16:43 17:13 06:43 17月8日MO O
  8月18日TU G 19 Aug WE 0697 HKG DEL 33G 19:05   21:27 20 Aug TH 00:28 00:58 08:23 21 8月FR 0694   DEL HKG 33K 01:30 02:30 10:45 11:15 07:15 MED HC
  8月22日SA G 23 8月SU G 24 8月MO G   25 Aug TU 0767 HKG SGN 33E 07:30 08:40 10:15 0766 SGN   HKG 33E 11:20 15:10 15:40 08:10 8月8日WE G
  8月27日TH G 28 8月FR 0699 HKG BOM 33G 16:20   17:30 21:20 21:50 08:00 8月SA 0696 BOM HKG 33G 21:30   8月30日8月20日07:00 07:30 07:30   HKG TPE 330 12:00 13:10 14:55 0564 TPE KIX 330
  16:05 20:00 20:30 07:30

Answer 1

试试这个正则表达式

(?=\d{2}\s+[A-Z][a-z]{2}\s+\w{2})(.+?)(?:(?=\d{2}\s+[A-Z][a-z]{2}\s+\w{2})|$)

<强> Regex Demo

正则表达式细分

(?=\d{2}\s+[A-Z][a-z]{2}\s+\w{2}) #This is the same thing that you have given in question as regex
  (.+?) #Lazy matching to match all the characters between the present lookahead till the next lookahead. If we use greedy matching, it will match all the way to the last which we don't want
(?:  #Non-capturing group..I am using because of \z
  (?=\d{2}\s+[A-Z][a-z]{2}\s+\w{2}) #Same lookahead as yours..It basically asserts the next position of the pattern you are searching..We want to capture whatever comes in between the two lookaheads
   | #Alternation
 $ #This is for capturing the last match because there will be no lookahead that follows the last one
)

注意： - 我正在使用s修饰符，因为我们还希望匹配\n（如果有）

PHP代码

$re = "/(?=\\d{2}\\s+[A-Z][a-z]{2}\\s+\\w{2})(.+?)(?:(?=\\d{2}\\s+[A-Z][a-z]{2}\\s+\\w{2})|$)/s"; 
$str = "31 Jul FR 0135 HKG MEL 33K 18:00 19:44 01 Aug SA\n06:40 07:10 11:10 02 Aug SU 0134 MEL HKG 33K 06:40 07:37 15:21 15:51 11:11 03 Aug MO G 04 Aug TU 0905 HKG MNL 330 20:50 22:52 05 Aug WE 00:58\n0912 MNL HKG 330 08:32 10:36 11:06 14:16 06 Aug TH T2024\nP2 19:00 19:00 07 Aug FR 00:30 00:30 05:30\nT2314 2R 22:00 22:00 08 Aug SA 06:00 06:00 08:00 09 Aug SU G 10 Aug MO G 11 Aug TU R13 06:00 06:00 06:06 06:06 00:06 0699 HKG BOM\n33G 16:20 17:53 21:07 21:37 07:47 12 Aug WE 13 Aug TH RPT 00:00 00:00 02:45 02:45 02:45 14 Aug FR 0660 BOM HKG 33G 03:05 04:15 12:48 13:18 07:43 15 Aug SA R13\n06:00 06:00 11:23 11:23 05:23 T1514 CW 14:00 14:00 19:30 19:30 05:30 16 Aug SU 0494 HKG TPE 33G 10:30 12:16 14:08\n0495 TPE HKG 33G 14:59 16:43 17:13 06:43 17 Aug MO O\n18 Aug TU G 19 Aug WE 0697 HKG DEL 33G 19:05 21:27 20 Aug TH 00:28 00:58 08:23 21 Aug FR 0694 DEL HKG 33K 01:30 02:30 10:45 11:15 07:15 MED HC\n22 Aug SA G 23 Aug SU G 24 Aug MO G 25 Aug TU 0767 HKG SGN 33E 07:30 08:40 10:15 0766 SGN HKG 33E 11:20 15:10 15:40 08:10 26 Aug WE G\n27 Aug TH G 28 Aug FR 0699 HKG BOM 33G 16:20 17:30 21:20 21:50 08:00 29 Aug SA 0696 BOM HKG 33G 21:30 22:30 30 Aug SU 07:00 07:30 07:30 31 Aug MO 0564 HKG TPE 330 12:00 13:10 14:55 0564 TPE KIX 330\n16:05 20:00 20:30 07:30"; 

preg_match_all($re, $str, $matches);

<强> Ideone Demo

正则表达式通配符和环视

1 个答案: