Question

基本上我想要问题这个词，Johnny有1个镍，4个角钱和3个季度。约翰尼有多少钱？（回答：1.20美元）但每次我改变它我的代码它都不起作用。

这是我编写的代码，需要帮助来更改单词问题。

<script>
 var person1, person2;

 function getPeople() {
     var people = ['Kritarth', 'Sharujan', 'Anveer', 'Krishna', 'Husnain', 'Iser', 'Ishan', 'Harman', 'Hemant', 'Harjot'];

     person1 = people[Math.floor(Math.random() * people.length)];
     person2 = people[Math.floor(Math.random() * people.length)];

     while (person1 === person2) {
         person2 = people[Math.floor(Math.random() * people.length)];
     }
 }

 function getrandomnumber(min, max, notin) {
     return min + Math.floor((max - min + 1) * Math.random());
 }

 function getoption(s, ch, num) {
     var a = s.split(ch);
     return a[num - 1];
 }

 var marymoney = getrandomnumber(50, 100, "");
 var johnmoney = getrandomnumber(50, 100, "");
 var maryitem = getrandomnumber(5, 20, "");
 var johnitem = getrandomnumber(5, 20, "");
 var marystuff = getoption("notebook,pencil,ruler,pen,eraser,binder,backpack", ",", getrandomnumber(1, 7));

 var johnstuff = getoption("notebook,pencil,ruler,pen,eraser,binder,backpack", ",", getrandomnumber(1, 7));

 while (marystuff === johnstuff) {
     johnstuff = getoption("notebook,pencil,ruler,pen,eraser,binder,backpack", ",", getrandomnumber(1, 7));
 }
 getPeople();
 var totalleft = marymoney + johnmoney - maryitem - johnitem;
 var str = person1 + " has $" + marymoney + " and " + person2 + " had $" + johnmoney + ". " + person1 + " buys a " + marystuff + " for $" + maryitem + " and " + person2 + " buys a " + johnstuff + " for $" + johnitem + ". They have $" + totalleft + ".";

 document.write(str);
</script>

Answer 1

//定义人员和项目列表 var people = ['Kritarth'，'Sharujan'，'Anveer'，'Krishna'，'Husnain'，'Iser'，'Ishan'，'Harman'，'Hemant'，'Harjot']; var items = ['notebook'，'pencil'，'ruler'，'pen'，'eraser'，'binder'，'backpack']; var cost = [20.00,8.00,11.00,15.00,5.00,35.00,100.00];

//获取唯一且随机的名称 function getList（list，amount）{ var index = 0，selected = [];

 while (amount-- > 0) {
         index = getRandom(0, list.length - 1);
     selected.push (list[index]);

     // Remove the selected member from the list
     list = list.slice(0, index).concat(list.slice(index + 1));
 }

 return selected;

}

//返回min和max之间的整数 function getRandom（min，max）{ 返回Math.floor（min + Math.random（）*（max - min + 1））; }

//显示结果 function showResults（）{ var population = 2;

var everyone = getList（人，人口）; var everything = getList（items，population）;

 var person = [];

//设置每个人的姓名，项目和金钱 for（var i = 0; i＆lt; population; i ++）{ person [i] = { 姓名：大家[i]， item：一切[i]，成本：成本[items.indexOf（everything [i]）]，钱：getRandom（50,100） } }

var totalleft = person [1] .money + person [0] .money - person [1] .cost - person [0] .cost;

  var str = person[1].name + " has $" + person[1].money + " and " +     person[0].name + " had $" + person[0].money + ". " +
         person[1].name + " buys a " + person[1].item + " for $" +  person[1].cost + " and " + person[0].name + " buys a " + person[0].item + " for $" + person[0].cost + ". " +
         "They have $" + totalleft + " left.";

document.getElementById（'output'）。innerHTML = str; }

//最初由Misa Chan编码，由David.Refoua.me改进 showResults（）;

我需要帮助来解决一个小问题

1 个答案: