Question

我在MySQL中有两个表 - tickets和ticket_updates

具有以下结构：

tickets

序列
ticketnumber
日期时间

ticket_updates

序列
ticketnumber
日期时间

关系是：tickets.ticketnumber = ticket_updates.ticketnumber

我想根据行插入ticket_updates

的时间找出某一天的平均响应时间

我尝试了这个查询：

SELECT avg(response_seconds) as s FROM 
    (SELECT time_to_sec(timediff(min(u.datetime), u.datetime)) AS response_seconds 
    FROM tickets t JOIN ticket_updates u ON t.ticketnumber = u.ticketnumber 
    WHERE u.type = 'update' and t.customer = 'Y' and DATE(u.datetime) = '2016-04-18' 
    GROUP BY t.ticketnumber) 
    AS r

但每次都会返回0.000

Answer 1

我认为问题在于：

(SELECT time_to_sec(timediff(min(u.datetime), u.datetime)) AS response_seconds

在我的控制台上返回0。试试：

( select time_to_sec( timediff( from_unixtime( floor( UNIX_TIMESTAMP(u.datetime)/60 )*60 ), u.datetime) ) ) as response_seconds;

像

SELECT avg(response_seconds) as s FROM 
    ( select time_to_sec( timediff( from_unixtime( floor( UNIX_TIMESTAMP(u.datetime)/60 )*60 ), u.datetime) ) ) as response_seconds 
    FROM tickets t JOIN ticket_updates u ON t.ticketnumber = u.ticketnumber 
    WHERE u.type = 'update' and t.customer = 'Y' and DATE(u.datetime) = '2016-04-18' 
    GROUP BY t.ticketnumber) 
    AS r

从两个数据库表中选择平均响应时间

1 个答案: