错误:'设置'对象没有属性.. - Python3

时间:2016-04-15 22:16:10

标签: class python-3.x dictionary pandas

我正在处理一个需要从pandas中获取表中的行的程序,并将每个行存储为一个字典条目,其中一列作为键,其他存储在具有该键的对象中。它似乎工作正常,当它循环将它们添加到字典时我没有错误,但是如果我尝试使用像SeqDict [' key']这样的语法来调用该字典中的特定项目.class属性,我收到错误说"'设置'对象没有属性' classattribute'。我使用了错误的语法还是我的代码还有其他问题?这是我第一次尝试编程,如果我犯了一个愚蠢的错误,或者我的代码写得非常低效,那就很抱歉。

我的代码的前半部分似乎工作正常

import os
import pandas as pd

print("Please move your CSV to the desktop before continuing.")
csvfilename = input("Enter the name of your CSV file: ")
desktopfilepath = os.path.expanduser("~/Desktop/")
csvfilepath = desktopfilepath + csvfilename

seqtable = (pd.read_csv(csvfilepath, 
                    dtype=str, 
                    header=0, 
                    usecols=["Well", "Core Sample ID", "Sample ID", "Exon"]))

newseqtable = pd.DataFrame.dropna(seqtable)
print(newseqtable)

y = len(newseqtable.index)
print(y, "files to rename.") 

我假设这部分是我做错事的地方

class SeqID:
    def __init__(self,well,sequence,exon):
        self.well = well
        self.sequence = sequence
        self.exon = exon
SeqDict = {}

x = 0
for x in range(y):
    ID = newseqtable.iat[x,1]
    well = newseqtable.iat[x,0]
    sequence = newseqtable.iat[x,2]
    exon = newseqtable.iat[x,3]
#    print(ID + "," + well + "," + sequence + "," + exon + ".") #This works fine when I choose to run it
    SeqDict[ID] = {SeqID(well,sequence,exon)}
SeqDict  #This prints the dictionary keys I would expect

SeqDict['key'].well  # This returns the error when I insert a key

由于

1 个答案:

答案 0 :(得分:2)

这一行:

SeqDict[ID] = {SeqID(well,sequence,exon)}

创建一组。你可能意味着:

SeqDict[ID] = SeqID(well,sequence,exon)