Question

def get_resources(*required):
    """
    This is to help building functions in the main calculator faster
    returns lists of resources needed, in the order requested
    """
    print('-'*30)
    a = ['acceleration', 0, 'a', 'm s⁻²', '.2f', 'scalar']
    A = ['amplitude', 0, 'A', 'm', '.2f', 'scalar']  # A: amplitude
    Em = ['combined mass', 0, '∑m', 'kg', '.2f', 'scalar']
    f = ['frequency', 0, 'f', 'Hz', '.1f', 'scalar']  # f: frequency (also m s⁻¹)
    F = ['force', 0, 'F', 'N', '.2f', 'scalar']
    g = ['gravity', 9.81, 'a', 'm s⁻²', '.2f', 'scalar']
    hl = ['wavelength', 0, 'λ', 'm', '.2f','vector']  # λ: wavelength
    m = ['mass', 0, 'm', 'kg', '.2f', 'scalar']
    m1 = ['mass1', 0, 'm1', 'kg', '.2f', 'scalar']
    m2 = ['mass2', 0, 'm2', 'kg', '.2f', 'scalar']
    t = ['time', 0, 't', 's', '.2f', 'scalar']
    T = ['tension', 0, 'T', 'N', '.1f', 'scalar']
    T = ['period', 0, 'T', 's', '.3f', 'scalar']  # T: Time PERIOD of oscillation in seconds (T = 2π√(m/k))
    v = ['wave speed', 0, 'v', 'm s⁻¹', '.2f', 'scalar']  # v: speed of a wave (v = fλ OR v = λ/T)
    v = ['velocity', 0, 'v', 'm s⁻¹', '.2f', 'scalar']
    v0 = ['initial velocity', 0, 'v₀', 'm s⁻¹', '.2f', 'vector']
    vf = ['final velocity', 0, 'vf', 'm s⁻¹', '.2f', 'vector']
    x = ['change in distance', 0, 'Δx', 'm', '.2f', 'scalar']
    x = ['distance', 0, 'x', 'm', '.2f', 'scalar']
    for i in required:
        for j in vars().items():
            if i == j[0]: print('{} = {}'.format(j[0], j[1]))

我正在尝试编写一个函数（接受参数），然后将它们与函数中的值进行比较，并打印所有可能的匹配项。但是，它不会打印所有可能的匹配项，只会打印与名称匹配的最终匹配项。另外我想在列表[1]位置使用字母字符，例如x = [＆＃39;距离＆＃39;，0，＆＃39; x＆＃39;，＆＃39; m＆＃39;，＆＃39; .2f＆＃39;，＆＃39;标量＆＃39;]＆gt; x = [＆＃39;距离＆＃39;，ABC，＆＃39; x＆＃39;，＆＃39; m＆＃39;，＆＃39; .2f＆＃39;，＆＃39;标量＆＃39; ]

目前如果我这样做

get_resources('x','F', 'T')

会打印

------------------------------
x = ['distance', 0, 'x', 'm', '.2f', 'scalar']
F = ['force', 0, 'F', 'N', '.2f', 'scalar']
T = ['period', 0, 'T', 's', '.3f', 'scalar']

但我想像这样打印。

------------------------------
x = ['change in distance', xc, 'Δx', 'm', '.2f', 'scalar']
x = ['distance', xc, 'x', 'm', '.2f', 'scalar']
F = ['force', Fc, 'F', 'N', '.2f', 'scalar']
T = ['tension', Tc, 'T', 'N', '.1f', 'scalar']
T = ['period', Tc, 'T', 's', '.3f', 'scalar']

如何重写此函数以根据需要返回结果？

Answer 1

这解决了这个问题，不幸的是我必须删除评论..啊好

def get_resources(*required): """ This is to help building functions in the main calculator faster returns lists of resources needed, in the order requested """ print('-'*30) longstring = \ "a = ['acceleration', ac, 'a', 'm s⁻²', '.2f', 'scalar'] | " \ "A = ['amplitude', 0, 'Ac', 'm', '.2f', 'scalar'] | " \ "Em = ['combined mass', Emc, '∑m', 'kg', '.2f', 'scalar'] | " \ "f = ['frequency', fc, 'f', 'Hz', '.1f', 'scalar'] | " \ "F = ['force', Fc, 'F', 'N', '.2f', 'scalar'] | " \ "g = ['gravity', 9.81, 'a', 'm s⁻²', '.2f', 'scalar'] | " \ "hl = ['wavelength', hlc, 'λ', 'm', '.2f', 'vector'] | " \ "KE = ['kinetic energy', KEc, 'KE', 'J', '.1f', 'scalar'] | " \ "m = ['mass', 0, 'mc', 'kg', '.2f', 'scalar'] | " \ "m1 = ['mass1', m1c, 'm1', 'kg', '.2f', 'scalar'] | " \ "m2 = ['mass2', m2c, 'm2', 'kg', '.2f', 'scalar'] | " \ "t = ['time', tc, 't', 's', '.2f', 'scalar'] | " \ "T = ['tension force', Tc, 'T', 'N', '.1f', 'scalar'] | " \ "T = ['period', Tc, 'T', 's', '.3f', 'scalar'] | " "v = ['wave speed', vc, 'v', 'm s⁻¹', '.2f', 'scalar'] | " \ "v = ['velocity', vc, 'v', 'm s⁻¹', '.2f', 'scalar'] | " \ "v0 = ['initial velocity', v0c, 'v₀', 'm s⁻¹', '.2f', 'vector'] | " \ "vf = ['final velocity', vfc, 'vf', 'm s⁻¹', '.2f', 'vector'] | " \ "W = ['work', Wc, 'W','J', '.2f', 'scalar'] # W: work (W = Fd) | " \ "x = ['change in distance', xc, 'Δx', 'm', '.2f', 'scalar'] | " \ "x = ['distance', xc, 'x', 'm', '.2f', 'scalar'] | " variables = (longstring.split('|')) for i in required: for j in variables: k = j.split('=') k[0] = k[0].strip() if i == k[0]: k[1] = k[1].strip() print('{} = {}'.format(k[0], k[1])) get_resources('m1', 'm2', 'T', 'a', 'g', 't', 'x', 'v0') get_resources('m','v','KE','x','F', 'T')

python3返回列表中的所有变量

1 个答案: