我是编程的初学者,从Python开始。我是Charles Severance博士的材料。所以在他的书中有一个例子:
import urllib
fhand = urllib.urlopen('http://www.py4inf.com/code/rom...
for line in fhand:
print line.strip()
当我将其粘贴到Python 2版本(我使用PyCharm 5.0.4)时,会出现:
Traceback (most recent call last):
File "D:/Python4yk/temprehg111.py", line 2, in <module>
fhand = urllib.urlopen('http://www.py4inf.com/code/rom...
File "C:\Python27\lib\urllib.py", line 87, in urlopen
return opener.open(url)
File "C:\Python27\lib\urllib.py", line 208, in open
return getattr(self, name)(url)
File "C:\Python27\lib\urllib.py", line 292, in open_http
import httplib
File "C:\Python27\lib\httplib.py", line 79, in <module>
import mimetools
File "C:\Python27\lib\mimetools.py", line 6, in <module>
import tempfile
File "C:\Python27\lib\tempfile.py", line 35, in <module>
from random import Random as _Random
File "random.py", line 3, in <module>
integers
NameError: name 'line' is not defined
当我输入另一个例子时,也会收到错误。怎么了?我甚至不写程序。我只是复制粘贴一个例子。问查克博士 - 仍然没有答案。
答案 0 :(得分:0)
试试这个:
import urllib
fhand = urllib.urlopen('http://www.py4inf.com')
for line in fhand:
print line.strip() # notice the indentation