Question

我有2个（mysql）表：

orders:
   order_number

deliveries:
   id, order_number, status

订单可以在交货表中进行多次交货。现在我查询了50个订单，然后循环它们（php）并查询交货表，其中order_number = orders.order_number并合并数组。

理想情况下，这是一个查询，而不是51.我已经尝试了100个连接和组的组合，但无法破解这个看似简单的查询。结果应该是：

[orders] => Array
    (
        [0] => Array
            (
                [order_number] => 16021322220558
                [deliveries] => Array
                    (
                        [0] => Array
                            (
                                [id] => 13332
                                [order_number] => 16021322220558
                                [status] => delivering
                            )
                        [1] => Array
                            (
                                [id] => 13333
                                [order_number] => 16021322220558
                                [status] => delivering
                            )
                    )

            )
        [1] => Array
            (
                [order_number] => 16021322220559
                [deliveries] => Array
                    (
                        [0] => Array
                            (
                                [id] => 13334
                                [order_number] => 16021322220559
                                [status] => delivering
                            )
                        [1] => Array
                            (
                                [id] => 13335
                                [order_number] => 16021322220559
                                [status] => delivering
                            )
                    )

            )
        ...
    )

编辑：这就是我最终的结果。 IN是从51个查询到2个的洞察力！

<?php
// Query for the last 50 orders
$q_orders['orders'] = // SELECT * FROM orders LIMIT 50

// Create array of order numbers
foreach($q_orders['orders'] as $order){
    $order_numbers[] = $order['order_number'];
}   

// Query for all the deliveries
$q_deliveries = // SELECT * FROM deliveries WHERE order_number IN ($order_numbers)

// For each order, append the deliveries with the same order_number
$i = 0;
foreach($q_orders['orders'] as $order){

    foreach($q_deliveries as $delivery){

        if($delivery['order_number'] == $order['order_number']){

            $q_orders['orders'][$i]['deliveries'][] = $delivery;

        }

    }

    $i++;

}

Answer 1

好的，所以我可以收集的内容，我会说：

SELECT id, orders.order_number, status
 FROM orders, deliveries
  WHERE orders.order_number = 'ordernumber'
   AND deliveries.order_number = orders.order_number

但是，我很困惑为什么你首先需要原始订单号。你可以直接从蝙蝠中选择deliveries.order_number，不能吗？像这样：

SELECT id, order_number, status
     FROM deliveries
      WHERE order_number = 'ordernumber'

现在有一些PHP魔法（我相信这应该有所不同，因此我现在无法测试它）

<?php
    $result = mysql_query($query);
    $result_array = array();

    while($row = mysql_fetch_array($result)){
      $result_array[] = $row;
    }
?>

对不起，我相信我现在明白你的问题了。在那种情况下，不，你不能使用mysql返回一个自然的基于PHP的多维数组。（mysql无法格式化特定语言的结果）

如果要更改结果的排序方式，则必须手动合并数组。

修改：对于多个订单查询

SELECT id, order_number, status
     FROM deliveries
      WHERE order_number IN (2323, 34, 25, 44646, 24, 26)

您需要使用IN。这意味着查询将获取任何这些订单号。使用像这样的php数组填充IN非常容易：

<?php
 $ordernumbers = implode(",", $arrayWithOrderNumbers);
 $query = "SELECT id, order_number, status
     FROM deliveries
      WHERE order_number IN ($ordernumbers)";
?>

IN基本上是此简称：WHERE order_number = 34 OR order_number = 35 OR order_number = 34

等。等

加入2个表，生成多维数组

1 个答案: