Question

下面的代码有效，虽然在运行事务时我创建了另一个PDO对象，但这并不会影响我的事务：

$dsn = 'mysql:host=' . "localhost" . ';dbname=' . "somedb";

$options = array(
    PDO::ATTR_PERSISTENT => true,
    PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
    PDO::ATTR_ORACLE_NULLS => PDO::NULL_TO_STRING
);

// first PDO object
$db = new \PDO($dsn, "someuser", "somepass", $options);

$db->beginTransaction();

$stmt = $db->prepare("INSERT INTO vbclient set company = 'test'");
$stmt->execute();

// second PDO object
$dbnew = new \PDO($dsn, "someuser", "somepass", $options);
$newstmt = $dbnew->prepare('select * from vbclient where clientID = 1');
$newstmt->execute();

$stmt = $db->prepare("INSERT INTO vbclient set company = 'test2'");
$stmt->execute();

$db->commit();

但是如果我将第二个PDO对象的创建放入一个单独的函数中，它似乎会终止第一个PDO对象的事务：

$dsn = 'mysql:host=' . "localhost" . ';dbname=' . "somedb";

$options = array(
PDO::ATTR_PERSISTENT => true,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::ATTR_ORACLE_NULLS => PDO::NULL_TO_STRING
);

// first PDO object
$db = new \PDO($dsn, "someuser", "somepass", $options);

$db->beginTransaction();

$stmt = $db->prepare("INSERT INTO vbclient set company = 'test'");
$stmt->execute();

secondPDO();

$stmt = $db->prepare("INSERT INTO vbclient set company = 'test2'");
$stmt->execute();

$db->commit();

function secondPDO() {

    $dsn = 'mysql:host=' . "localhost" . ';dbname=' . "somedb";

    $options = array(
        PDO::ATTR_PERSISTENT => true,
        PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
        PDO::ATTR_ORACLE_NULLS => PDO::NULL_TO_STRING
    );

    // second PDO object
    $dbnew = new \PDO($dsn, "someuser", "somepass", $options);
    $newstmt = $dbnew->prepare('select * from vbclient where clientID = 1');
    $newstmt->execute();

}

我收到错误“没有活动的交易。”我知道如果我用另一个实例覆盖PDO句柄，通常会发生这种情况。但我不这样做，只有当第二个PDO对象在另一个函数中时才会出现错误。

为什么会这样？感谢。

PHP：一个PDO实例中断了其他PDO实例的事务

0 个答案: