Qpython,套接字连接错误

时间:2016-04-02 12:28:02

标签: sockets python-3.x qpython3

我正在学习服务器端和客户端连接: 我试图做的是在 Qpython (android)上连接服务器端和客户端脚本

问题是,当我运行它时,它给了我这个:

  

“ConnectionRefusedError:Errno [111] Connection Refused”

当我在计算机上运行相同的脚本时,它没有给我任何错误。

背景资料:

  • 我在手机上使用了2个不同的应用

  • 我的电脑上有1个。

    但我想这不可能是问题

  

客户端

import socket 
import sys 

HOST, PORT = "localhost", 9999 

Data = " ".join(sys.argv[1:]) + input(" Enter Message:\n"

# Create a socket (SOCK_STREAM means a TCP socket) 

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM) 

try: 
 # Connect to server and send data
 sock.connect((HOST, PORT))
 sock.sendall(bytes(data + "\n", "utf-8")) 
# Receive data from the server and shut down 
 received = str(sock.recv(1024), "utf-8")
finally: 
 sock.close() 

print("Sent: {}".format(data)) 
print("Received: {}".format(received))
  

服务器

import socketserver 

class MyTCPHandler(socketserver.BaseRequestHandler): 

 def handle(self): 

  # self.request is the TCP socket connected to the client 

  self.data = self.request.recv(1024).strip() 
  print("{} wrote:".format(self.client_address[0])) 
  print(self.data) 
# just send back the same data, but upper-cased 

self.request.sendall(self.data.upper()) 

if __name__ == "__main__": 
 HOST, PORT = "localhost", 9999 

# Create the server, binding to localhost on port 9999 

 server = socketserver.TCPServer((HOST, PORT), MyTCPHandler) 
server.serve_forever()

0 个答案:

没有答案