Question

我有一个包含以下值的表

   ACCNO                  TEXT
   -------------     ----------------
   8611004050001     internal payment
   861100405000X     external payment
   8611XXXXXXXXX     other payments

假设如果accono是8611004050002那么我必须拍照外部付款。如果accno是8611211216223，那么我必须得到其他付款。

我需要获得最接近的匹配值是单个sql我尝试过case语句它不起作用。实现这一目标的有效方法是什么。

请帮助我

Answer 1

嗯，一种方法使用巨大的case语句。像这样：

select t.*
from t
order by (case when accno = <accno> then 99
               when left(accno, 15) = left(<accno>, 15) then 15
               when left(accno, 14) = left(<accno>, 14) then 14
               when left(accno, 13) = left(<accno>, 13) then 13
               when left(accno, 12) = left(<accno>, 12) then 12
               when left(accno, 11) = left(<accno>, 11) then 11
               when left(accno, 10) = left(<accno>, 10) then 10
               when left(accno, 9) = left(<accno>, 9) then 9
               when left(accno, 8) = left(<accno>, 8) then 8
               when left(accno, 7) = left(<accno>, 7) then 7
               when left(accno, 6) = left(<accno>, 6) then 6
               when left(accno, 5) = left(<accno>, 5) then 5
               when left(accno, 4) = left(<accno>, 4) then 4
               when left(accno, 3) = left(<accno>, 3) then 3
               when left(accno, 2) = left(<accno>, 2) then 2
               when left(accno, 1) = left(<accno>, 1) then 1
               else 0
          end) desc
fetch first 1 row only;

获取DB2 sql中最接近的匹配值

1 个答案: