我在春天mvc的ajax请求
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/json2/20150503/json2.js"></script>
<script>
$(document).ready(function(){
var producer = "producer";
var model = "model";
var price = "1";
var ResponseModel = {};
ResponseModel.producer=producer;
ResponseModel.model=model;
ResponseModel.price=price;
$.ajax({
url : '/ajaxtest',
data: JSON.stringify({"editUserRequest":ResponseModel}),
type: "POST",
async: true,
beforeSend: function(xhr) {
xhr.setRequestHeader("Accept", "application/json");
xhr.setRequestHeader("Content-Type", "application/json");
},
success : function(data) {
alert("success");
console.log(data);
},
error:function(data) {
alert("errorxxx");
console.log(data);
}
});
});
</script>
模型
@JsonSerialize
public class ResponseModel implements Serializable {
public ResponseModel(){}
public String getProducer() {
return producer;
}
public void setProducer(String producer) {
this.producer = producer;
}
public String getModel() {
return model;
}
public void setModel(String model) {
this.model = model;
}
public String getPrice() {
return price;
}
public void setPrice(String price) {
this.price = price;
}
private String producer;
private String model;
private String price;
}
和spring MVC控制器
@Controller
@RequestMapping("/")
public class HelloController {
@RequestMapping(method = RequestMethod.GET)
public String printWelcome(ModelMap model) {
model.addAttribute("message", "Hello world!");
return "hello";
}
//@ModelAttribute(value="editUserRequest")
@RequestMapping(value = "/ajaxtest", method = RequestMethod.POST,consumes=MediaType.APPLICATION_JSON_VALUE, produces = MediaType.APPLICATION_JSON_VALUE)
public @ResponseBody
String getTime(@ModelAttribute(value="editUserRequest") ResponseModel editUserRequest,HttpServletRequest request,HttpServletResponse response) {
String result = editUserRequest.getModel()+editUserRequest.getPrice()+editUserRequest.getProducer();
//String result = "editUserRequest";
//System.out.println("Debug Message from CrunchifySpringAjaxJQuery Controller.." + new Date().toString());
return result;
}
}
web.xml是
<web-app version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>Spring MVC Application</display-name>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
和调度程序servlet是
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<context:component-scan base-package="com.springapp.mvc"/>
<context:annotation-config />
<mvc:annotation-driven />
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/pages/"/>
<property name="suffix" value=".jsp"/>
</bean>
</beans>
在firebug中发送ajax请求后,显示null结果通过post在ajax错误中成功完成。
我有<jackson.version>2.6.3</jackson.version>
<!-- Need this for json to/from object -->
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-core</artifactId>
<version>${jackson.version}</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>${jackson.version}</version>
</dependency>
但是不能在Spring MVC 4 json中使用它映射到java对象。如何解决?
答案 0 :(得分:1)
好的我已经在我的机器上复制了你的问题。要以对象的形式将ajax调用中的数据发送到spring mvc,您需要对ajax调用进行一些更改,并且需要将@ModelAttribute更改为@RequestBody。请参阅下面的更新代码
$(document).ready(function(){
var producer = "producer";
var model = "model";
var price = "1";
var editUserRequest = new Object();
editUserRequest.producer=producer;
editUserRequest.model=model;
editUserRequest.price=price;
$.ajax({
url : 'ajaxtest',
data: JSON.stringify(editUserRequest),
type: "POST",
contentType : 'application/json; charset=utf-8',
dataType : 'json',
success : function(data) {
alert("success");
console.log(data);
},
error:function(data) {
alert("errorxxx");
console.log(data);
}
});
});
Spring Controller方法
@RequestMapping(value = "ajaxtest", method = RequestMethod.POST,consumes=MediaType.APPLICATION_JSON_VALUE, produces = MediaType.APPLICATION_JSON_VALUE)
public @ResponseBody
ResponseModel getTime(@RequestBody ResponseModel editUserRequest) {
String result = editUserRequest.getModel()+editUserRequest.getPrice()+editUserRequest.getProducer();
//String result = "editUserRequest";
//System.out.println("Debug Message from CrunchifySpringAjaxJQuery Controller.." + new Date().toString());
return editUserRequest;
}
因为在ajax调用中你期待一个JSON响应,并且你从spring控制器返回一个普通的String。它转到ajax调用中的错误处理程序。我已将spring控制器方法的响应类型更改为ResponseModel,以便响应将采用JSON格式,并且在ajax调用中控件转到成功处理程序。