如何将mySQL转换为PDO

时间:2016-03-20 14:44:54

标签: php mysql pdo

我有这个PHP脚本,用于使用mySQL将通知发布到数据库。我想将其更改为使用PDO。

我原来的代码在这里:

<?php
require_once"connection.php";
    session_start();

if(isset($_POST['annForm'])) 
{

$userID=$_SESSION['sessionUser'];
$idQuery=mysql_query("SELECT adminID FROM administrator WHERE username='$userID'");         
$adminID=mysql_fetch_array($idQuery);       


$genAnnouncement=$_POST['annForm'];
$genAnnouncement=mysql_real_escape_string($genAnnouncement);
$addGenAnnQuery="INSERT INTO generalannouncement (adminID, genAnnouncement) VALUES('$adminID[0]','$genAnnouncement')";
$announcementAdded=mysql_query($addGenAnnQuery);
if(!$announcementAdded)
{
    echo 'Could Not Add Announcement, Try Again Later.<br>';
    echo mysql_error();
}
    else
        echo 'Announcement Added Successfully.<br>';
        header( "refresh:500;url=adminsHomepage.php" );
        return;
        mysql_close($con);  
}   
?>

我已经修改了代码以使用PDO,但我现在在第24行遇到未定义索引$ adminID [0]和第25行且出现完整性约束违规的错误:1048列'adminID'不能为空。修改后的代码如下:

require_once"connection.php";

session_start();


if(isset($_POST['annForm'])) 
{
$userID=$_SESSION['sessionUser'];   
$idQuery= $conn->prepare("SELECT adminID FROM administrator WHERE username='$userID'");
$idQuery->execute();
$adminID= $idQuery->fetch();    

$genAnnouncement=$_POST['annForm'];


if (isset($genAnnouncement)) 
{
$sql = "INSERT INTO generalannouncement (adminID, genAnnouncement)
           VALUES (:adminID, :genAnnouncement)";
$stmt = $conn->prepare($sql);
$stmt->execute(array(
    ':adminID' => $_POST['$adminID[0]'],
    ':genAnnouncement' => $_POST['annForm']));

echo 'Announcement Added Successfully.<br>';
header( "refresh:500; url= adminsHomepage.php");
return;
}}

2 个答案:

答案 0 :(得分:3)

在原始MySQL_查询中,您有:

$addGenAnnQuery = "
        INSERT INTO generalannouncement 
                    (adminID, genAnnouncement) 
             VALUES ('$adminID[0]','$genAnnouncement')
";

因此,如果您的旧查询有效,则新execute必须为:

$stmt->execute(array(
    ':adminID' => $adminID[0],
    ':genAnnouncement' => $genAnnouncement));

答案 1 :(得分:2)

我想,你这里有问题:$_POST['$adminID[0]'] 只是尝试删除撇号。