我的代码无法显示db的图片?

时间:2016-03-18 03:56:14

标签: php

使用php时请帮助无法显示图像

$result = mysql_query("SELECT * FROM obs") or die(mysql_error());
echo "<center><table><tr><th width=200>Obs Number</th><th width=200>Name</th><th width=200>Purpose</th><th width=200>Date Of OB</th><th width=200>Destination</th><th width=200>Image</th></tr></center>";
while ($row = mysql_fetch_array($result)) {
    echo '<tr>';

    //cant display image

    echo '<tr> <input type="hidden" name="showimage[]" value="'. $row['OBS_NUMBER'].'" >';
    echo '<td width=200>' . $row['OBS_NUMBER'] . '</td>';
    echo '<td width=200>' . $row['NAME'] . '</td>';
    echo '<td width=200>' . $row['PURPOSE'] . '</td>';
    echo '<td width=200>' . $row['DATE_OF_OB'] . '</td>';
    echo '<td width=200>' . $row['DESTINATION'] . '</td>';
    echo '<td width=200> <img src="data:image/jpeg;base64,' . base64_encode($row['imagesobs']) . '" width="250"></td>';
    echo '</tr>';
}

0 个答案:

没有答案