Question

错误：INSERT INTO预订（GameID，Name，Numberofdays，ReservationID，Startdate）VALUES（5，'jp'，4 ,,'2016-03-23'）您的SQL语法有错误;查看与您的MariaDB服务器版本对应的手册，以便在第30行结果“2016-03-23”附近使用正确的语法

即使SQL查询正确，下面的代码也会插入从表单输入的信息。我已经多次测试和更改了代码，并与同行讨论并进行了审核。

Bellow是它的代码：

    <div id="content">  
<?php

//variables needed to connect to the database
    $user_name = "root";
    $password = "";
    $database = "game_library";
    $host_name ="localhost";

// Create connection
    $con=mysqli_connect($host_name,$user_name,$password,$database) or die("Error ");
    // Check connection
    if ($con->connect_error) {
        die("Connection failed: " . $con->connect_error);
    } 
 //link the search term to the html page
    $GameID=$_POST['GameID'];
    $Name=$_POST['Name'];
    $Numberofdays=$_POST['Numberofdays'];
    $Startdate=$_POST['Startdate'];

    //sql query to add the data from the form elements to the sql database
    //The reservationID is auto incremented so requires a space 
    $qry_reserve = "INSERT INTO reservations 
    (GameID,Name,Numberofdays,ReservationID,Startdate)VALUES ($GameID,'$Name',
    $Numberofdays, ,'$Startdate')";

    //Runs the query if the database if connection succesful
    if ($con->query($qry_reserve) === TRUE) {
    echo '<br/>';
    echo $Name. ' has been added successfully</h2>';
    echo '<hr>';
    } else {
    echo "Error: " . $qry_reserve . "<br>" . $con->error;
    }

    //show added data & all records to prove they have been added. You don't have to do this
    $qry_show_table = "SELECT * FROM reservations WHERE GameID='$GameID' ";
    $result = mysqli_query($con, $qry_show_table);

    if (mysqli_num_rows($result) > 0) { // checks if there are more than zero rows returned.
        // output data of each row
        while($row = mysqli_fetch_assoc($result)) //puts all the results into an associative array that we can loop through
        {
        echo '<br/>';
        echo 'Name: '.$row['Name'];
        echo '<br/> GameID: '.$row['GameID'];
        echo '<br/> Startdate: '.$row['Startdate'];
        echo '<br/> Numberofdays: '.$row['Numberofdays'];
        echo '<br/>';
        echo '<hr>';
        }
} else {
echo "0 results";
}

$con->close();
?>

Answer 1

省略括号：

INSERT INTO reservations 
    VALUES ($GameID, '$Name', $Numberofdays, ??,' $Startdate')
---------------------------------------------^ something needs to go here

或者，更好的是，列出列：

INSERT INTO reservations(col1, col2, col3, col4, col5)
    VALUES ($GameID, '$Name', $Numberofdays, ??, '$Startdate')
---------------------------------------------^ something needs to go here

请注意，您有两个逗号，两者之间没有任何值。也许这是一个错字，也许你打算NULL或DEFAULT或其他东西。

Answer 2

您不需要括号，还有一个额外的逗号：

$qry_reserve = "INSERT INTO reservations VALUES ($GameID,'$Name',$Numberofdays,'$Startdate'";

http://www.w3schools.com/sql/sql_insert.asp的更多信息。

PHP语法错误：“检查与您的MariaDB服务器版本对应的手册以获得正确的语法”

2 个答案: