Question

如果不满足某些条件（例如总和或计数为零），是否有办法在reduce视图中不包含结果？

我的情况有点复杂，但为了简单起见，我们假设我们将航班预订作为文件进入。我也有航班时刻表，可用座位在同一个桶中。我的地图功能看起来像这样：

function (doc, meta) {
  if (meta.id.match(/^flight./)) {
    emit([doc.flighno, doc.schedule], {"availableSeats", doc.availableSeats});
  }
  else if (meta.id.match(/^request\./) && doc.status = "pending") {
    emit([doc.flighno, doc.schedule], {"requestedSeats", doc.requestedSeats});
  }
}

然后地图函数将发出这些行（我使用这种人类可读格式schedule只是为了让它更容易阅读。）：

"rows"=:[
{"id":"flight.123456", "key":["AC783","2016-05-04UTC"], "value":{"availableSeats":20}},
{"id":"request.1001",  "key":["AC783","2016-05-04UTC"], "value":{"requestedSeats":2} },
{"id":"request.1002",  "key":["AC783","2016-05-04UTC"], "value":{"requestedSeats":3} },
{"id":"request.1003",  "key":["AC783","2016-05-04UTC"], "value":{"requestedSeats":5} },
{"id":"flight.654321", "key":["AC783","2016-05-11UTC"], "value":{"availableSeats":50}},
{"id":"request.2001",  "key":["AC783","2016-05-11UTC"], "value":{"requestedSeats":5} },
{"id":"request.2002",  "key":["AC783","2016-05-11UTC"], "value":{"requestedSeats":25}},
{"id":"request.2003",  "key":["AC783","2016-05-11UTC"], "value":{"requestedSeats":35}},
{"id":"flight.999999", "key":["AC123","2016-05-13UTC"], "value":{"availableSeats":0} },
{"id":"request.3001",  "key":["AC123","2016-05-13UTC"], "value":{"requestedSeats":5} },
{"id":"request.3002",  "key":["AC123","2016-05-13UTC"], "value":{"requestedSeats":15}},
{"id":"request.3003",  "key":["AC123","2016-05-13UTC"], "value":{"requestedSeats":35}},
{"id":"flight.888888", "key":["AC124","2016-05-13UTC"], "value":{"availableSeats":45}},
{"id":"flight.777777", "key":["AC125","2016-05-13UTC"], "value":{"availableSeats":40}},
{"id":"request.4001",  "key":["AC125","2016-05-13UTC"], "value":{"requestedSeats":10}},
{"id":"request.4002",  "key":["AC125","2016-05-13UTC"], "value":{"requestedSeats":10}},
{"id":"request.4003",  "key":["AC125","2016-05-13UTC"], "value":{"requestedSeats":20}}
]

在我的情况下，我希望有一个reduce函数，用于汇总航班文档以及请求文档中可用席位的总和。我能得到的最远的是：

function(key, values, rereduce) {
  var result = {availableSeats: 0, waiting: 0, toProcess: false};
  for(var i=0; i < values.length; i++) {
    if (values[i].availableSeats > 0) {
      result.availableSeats += values[i].availableSeats;
    }
    if (values[i].requestedSeats > 0) {
      result.requestedSeats += values[i].requestedSeats;
    }
  }
  result.toProcess = Math.min(result.availableSeats, result.requestedSeats) > 0;
  return result;
}

缩小视图的结果将是：

"rows"=:[
{"key":["AC783","2016-05-04UTC"], "value":{"availableSeats":20, "requestedSeats": 10, "toProcess": true}},
{"key":["AC783","2016-05-11UTC"], "value":{"availableSeats":50, "requestedSeats": 60, "toProcess": true}},
{"key":["AC123","2016-05-13UTC"], "value":{"availableSeats":0,  "requestedSeats": 55, "toProcess": false}},
{"key":["AC124","2016-05-13UTC"], "value":{"availableSeats":45, "requestedSeats": 0,  "toProcess": false}},
{"key":["AC125","2016-05-13UTC"], "value":{"availableSeats":40, "requestedSeats": 40, "toProcess": true}}
]

但是，基本上，我需要的是让视图只包含availableSeats和requestedSeats都为正的键，即toProcess标志为真。我的大多数结果都会将其中一个值设为零，因此，与它们无关，加载整个视图（总是会增长），并不理想。

有什么建议吗？

更新：

我试着这样做：

if (result.tbd) {
  return(result);
}
else {
  return null;
}

以及

if (result.tbd) {
  return(result);
}
else {
  return {};
}

除了值null或{}之外，我不想要显示的键仍然显示，如下所示：

"rows"=:[
{"key":["AC783","2016-05-04UTC"], "value":{"availableSeats":20, "requestedSeats": 10, "toProcess": true}},
{"key":["AC783","2016-05-11UTC"], "value":{"availableSeats":50, "requestedSeats": 60, "toProcess": true}},
{"key":["AC123","2016-05-13UTC"], "value":null},
{"key":["AC124","2016-05-13UTC"], "value":null},
{"key":["AC125","2016-05-13UTC"], "value":{"availableSeats":40, "requestedSeats": 40, "toProcess": true}}
]

或

"rows"=:[
{"key":["AC783","2016-05-04UTC"], "value":{"availableSeats":20, "requestedSeats": 10, "toProcess": true}},
{"key":["AC783","2016-05-11UTC"], "value":{"availableSeats":50, "requestedSeats": 60, "toProcess": true}},
{"key":["AC123","2016-05-13UTC"], "value":{}},
{"key":["AC124","2016-05-13UTC"], "value":{}},
{"key":["AC125","2016-05-13UTC"], "value":{"availableSeats":40, "requestedSeats": 40, "toProcess": true}}
]

这与我最初的结果并没有太大差别，因为带有这些键的行数会增长很多。

Answer 1

你已经到了一半了。您只需检查toProcess标志并返回空结果{availableSeats: 0, waiting: 0, toProcess: false}，如果它是假的而不是您计算的实际值。这样，您不想要的结果将不会传播到rereduce步骤，也不会被计算在内。

从Couchbase map / reduce视图中的reduce中排除键

1 个答案: