Question

我的文本文件的值为

"444","/5"," ", " "," john""66""88"

我想只获得带双引号的值分裂后我想要七个字符串如下所示

first = "444"
second = "/5"
third = " "
fourth =" "
fifth  = "john"
sixth= "66"
seven= "88"

.Split("' '")似乎无法正常工作

Answer 1

使用正则表达式而不是拆分，如果由于某种原因在引用文本中有逗号并且您用逗号分割，那么您的数据将被破坏。

使用此：

Regex reg = new Regex("\"([^\"]*?)\"");

List<string> elements = new List<string>();

var matches = reg.Matches(theExpression);

foreach(Match match in matches)
{
    var theData = match.Groups[1].Value;
    elements.Add(theData);
}

//Now you have in elements a list with all 
//the values from the string properly splitted.

Answer 2

修改

我刚刚发现，您的部件可能不会以逗号分隔。这是一种基于char的方法：

前

您可以像这样尝试

string s = "\"444\",\"/5\",\" \", \" \",\" john\"\"66\"\"88\"";

var myParts = new List<string>();
int pos1 = s.IndexOf('"');
if (pos1 == -1)
    throw new Exception("No qoutes!");
int pos2 = s.IndexOf('"', pos1 + 1);
if (pos1 == -1)
    throw new Exception("No second quote!");

while (true) {
    myParts.Add(s.Substring(pos1, pos2 - pos1 + 1));
    pos1 = s.IndexOf('"', pos2 + 1);
    if (pos1 == -1)
        break;
    pos2 = s.IndexOf('"', pos1 + 1);
    if (pos2 == -1)
        throw new Exception("No final closing quote!");
};

使用c＃在双引号中拆分值

2 个答案:

修改

前