我正在尝试创建一个接受入站连接的Tcp服务器,并异步向连接的客户端发送消息。 有一个Tcp服务器示例,但它使用的是网关,即请求/响应,不支持异步。
我的目标,
TcpReceivingChannelAdapter
?)TcpSendingMessageHandler
?)从参考文档中,我应该使用Collaborating Outbound和Inbound Channel Adapters。但是没有java配置示例。我不明白如何使用java配置执行此操作,尤其是查找客户端的方式和位置。
我需要两个频道吗?一个用于入站,一个用于出站? inboundAdapter-> fromTcpChannel->消费者 生产者 - > outboundAdapter-> toTcpChannel
我是否创建ServiceActivator
或端点作为消费者/制作人?
Spring默认情况下,spring集成是否保持连接?当我需要向它发送消息时,只需将ip_connectId标头添加到消息中?
我是使用TcpSendingMessageHandler
将邮件发送给客户还是需要实施gateway
?
清理我的代码并在Gary的帮助下再次测试,这是我的代码到目前为止。
@EnableIntegration
@IntegrationComponentScan
@Configuration
public class IntegrationConfig implements
ApplicationListener<TcpConnectionEvent> {
@Value("${listen.port:8000}")
private int port;
@Bean //for accepting text message from TCP, putty
public MessageChannel fromTcp() {
return new DirectChannel();
}
@Bean //for sending text message to TCP client, outbound
public MessageChannel toTcp() {
return new DirectChannel();
}
// receive from MVC controller
@Bean
public MessageChannel invokeChannel() {
return new DirectChannel();
}
@Bean //inbound, it is working, I could read the inbound message while debugging
public TcpReceivingChannelAdapter in(
AbstractServerConnectionFactory connectionFactory) {
TcpReceivingChannelAdapter adapter = new TcpReceivingChannelAdapter();
adapter.setOutputChannel(fromTcp());
adapter.setConnectionFactory(connectionFactory);
return adapter;
}
//transform TCP bytes to string message, working
@Transformer(inputChannel = "fromTcp", outputChannel = "toCollaborate")
public String convert(byte[] bytes) {
return new String(bytes);
}
MessageHeaders staticheader; //save ip_connectinId, use this to collaborate outbound message later, for testing purpose only
@ServiceActivator(inputChannel = "toCollaborate", outputChannel = "toTcp")
public Message<String> handleTcpMessage(Message<String> stringMsg) {
staticheader = stringMsg.getHeaders();
return stringMsg;
// save the header, collaborate to output channel
}
//collaborate message from REST API invokeChannel to a outbound tcp client, this fail
@Transformer(inputChannel = "invokeChannel", outputChannel = "toTcp")
public Message<String> headerBeforeSend(String test) {
GenericMessage<String> msg = new GenericMessage<String>(
"from rest api");
if (staticheader != null) {
MessageBuilder
.fromMessage(msg)
.setHeader("ip_connectionId",
staticheader.get("ip_connectionId")).build();
}
return msg;
}
@ServiceActivator(inputChannel = "toTcp")
@Bean
public TcpSendingMessageHandler out(
AbstractServerConnectionFactory connectionFactory) {
TcpSendingMessageHandler tcpOutboundAdp = new TcpSendingMessageHandler();
tcpOutboundAdp.setConnectionFactory(connectionFactory);
return tcpOutboundAdp;
}
// should need only 1 factory? and keep connectin alive
// server for in coming connection
@Bean
public AbstractServerConnectionFactory serverCF() {
return new TcpNetServerConnectionFactory(this.port);
}
@Override
public void onApplicationEvent(TcpConnectionEvent tcpEvent) {
// TODO Auto-generated method stub
TcpConnection source = (TcpConnection) tcpEvent.getSource();
}
}
//The MVC controller
@Autowired
MessageChannel invokeChannel;
@RequestMapping(value="/invoke")
public String sayHello()
{
//trigger gateway to send a message
String msg = "hello";
MessagingTemplate template = new MessagingTemplate();
template.send(invokeChannel, new GenericMessage<String>(msg));
return msg;
}
测试结果:
1. putty连接好,发短信
2. SI收到消息确定
3.使用REST API localhost/webappname/rest/invoke
向invokeChannel发送消息,确定
4. transformer
设置邮件标题
5.例外如下
exception org.springframework.web.util.NestedServletException:Request 处理失败;嵌套异常是 org.springframework.messaging.MessageHandlingException:无法找到 出站套接字 org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:981) org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:860) javax.servlet.http.HttpServlet.service(HttpServlet.java:622) org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:845) javax.servlet.http.HttpServlet.service(HttpServlet.java:729) org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
答案 0 :(得分:1)
是;默认情况下连接保持打开状态;是的,您可以使用@ServiceActivator
来处理请求;是的,你只需要设置连接ID头。
要在Java Configuration中配置出站适配器,请将@ServiceActivator
添加到处理程序bean ...
@Bean
public TcpReceivingChannelAdapter() in() {
...
adapter.setOutputChannel(newRequests());
}
...
@ServiceActivator(inputChannel="toClientChannel")
@Bean
public TcpSendingMessageHandler out() {
...
}