Question

我在spark-streaming应用程序中遇到错误，我正在使用kafka作为输入流。当我使用socket时，它运行正常。但是，当我改为卡夫卡时，它给出了错误。任何人都知道为什么它会抛出错误，我是否需要更改批处理时间并检查指点时间？

错误StreamingContext：启动上下文时出错，将其标记为已停止 java.lang.StackOverflowError的

我的节目：

def main(args: Array[String]): Unit = {

    // Function to create and setup a new StreamingContext
    def functionToCreateContext(): StreamingContext = {
      val conf = new SparkConf().setAppName("HBaseStream")
      val sc = new SparkContext(conf)
      // create a StreamingContext, the main entry point for all streaming functionality
      val ssc = new StreamingContext(sc, Seconds(5))
      val brokers = args(0)
      val topics= args(1)
      val topicsSet = topics.split(",").toSet
      val kafkaParams = Map[String, String]("metadata.broker.list" -> brokers)
      val messages = KafkaUtils.createDirectStream[String, String, StringDecoder, StringDecoder](
        ssc, kafkaParams, topicsSet)

      val inputStream = messages.map(_._2)
//    val inputStream = ssc.socketTextStream(args(0), args(1).toInt)
      ssc.checkpoint(checkpointDirectory)
      inputStream.print(1)
      val parsedStream = inputStream
        .map(line => {
          val splitLines = line.split(",")
          (splitLines(1), splitLines.slice(2, splitLines.length).map((_.trim.toLong)))
        })
      import breeze.linalg.{DenseVector => BDV}
      import scala.util.Try

      val state: DStream[(String, Array[Long])] = parsedStream.updateStateByKey(
        (current: Seq[Array[Long]], prev: Option[Array[Long]]) =>  {
          prev.map(_ +: current).orElse(Some(current))
            .flatMap(as => Try(as.map(BDV(_)).reduce(_ + _).toArray).toOption)
        })

      state.checkpoint(Duration(10000))
      state.foreachRDD(rdd => rdd.foreach(Blaher.blah))
      ssc
    }
    // Get StreamingContext from checkpoint data or create a new one
    val context = StreamingContext.getOrCreate(checkpointDirectory, functionToCreateContext _)
  }
}

Answer 1

尝试删除检查点目录。

我不确定，但似乎您的流式传输上下文无法从检查点恢复。

无论如何，它对我有用。

Spark Streaming，kafka：java.lang.StackOverflowError

1 个答案: