Question

我有一个关键字列表，我想使用Google验证其使用情况。例如，如果“免费住宅”（带引号）在Google中返回结果，我会认为“免费住房”是常用的。

问题是，如果谷歌没有结果，我的代码崩溃了（KeyError）。如何绕过此错误？

（最后，如果谷歌没有结果，我想从我的关键字列表中删除该关键字。）

这是我的代码：

import json
import urllib

def showsome(searchfor):
  query = urllib.urlencode({'q': searchfor})
  url = 'http://ajax.googleapis.com/ajax/services/search/web?v=1.0&%s' % query
  search_response = urllib.urlopen(url)
  search_results = search_response.read()
  results = json.loads(search_results)
  data = results['responseData']
  print 'Total results: %s' % data['cursor']['estimatedResultCount']
  hits = data['results']
  print 'Top %d hits:' % len(hits)
  for h in hits: print ' ', h['url']
  print 'For more results, see %s' % data['cursor']['moreResultsUrl']

showsome('"this is not searched searched in Google"')

和追溯：

KeyError                                  Traceback (most recent call last)
c:\users\nathan\appdata\local\temp\tmpuj7hhu.py in <module>()
     15   print 'For more results, see %s' % data['cursor']['moreResultsUrl']
     16 
---> 17 showsome('"this is not searched searched in Google"')

c:\users\nathan\appdata\local\temp\tmpuj7hhu.py in showsome(searchfor)
      9   results = json.loads(search_results)
     10   data = results['responseData']
---> 11   print 'Total results: %s' % data['cursor']['estimatedResultCount']
     12   hits = data['results']
     13   print 'Top %d hits:' % len(hits)

KeyError: 'estimatedResultCount'

Answer 1

有两种方法可以处理错误。由于您在dict中进行多次查找，因此将其全部包含在try/except块中是一个不错的选择

import json
import urllib

def showsome(searchfor):
  query = urllib.urlencode({'q': searchfor})
  url = 'http://ajax.googleapis.com/ajax/services/search/web?v=1.0&%s' % query
  search_response = urllib.urlopen(url)
  search_results = search_response.read()
  results = json.loads(search_results)
  try:
      data = results['responseData']
      print 'Total results: %s' % data['cursor']['estimatedResultCount']
      hits = data['results']
      print 'Top %d hits:' % len(hits)
      for h in hits: print ' ', h['url']
      print 'For more results, see %s' % data['cursor']['moreResultsUrl']
  except KeyError:
      print "I'm gettin' nuth'in man"

showsome('"this is not searched searched in Google"')

在Google中搜索结果时绕过KeyError

1 个答案: