请参阅下面的代码和预期结果的图片
视图的新查询给出了同样错误的结果
select VW_DAWN_FRIDAY.*, invoice_no from VW_DAWN_FRIDAY
inner join cl$invoices
on cl$invoices.project_id = VW_DAWN_FRIDAY.project_id
SELECT DISTINCT VW_Learners_Train_Cost.learner_id,
VW_Learners_Train_Cost.project_id,
VW_Learners_Train_Cost.client_name,
VW_Learners_Train_Cost.FIRST_NAME,
VW_Learners_Train_Cost.LAST_NAME,
VW_Learners_Train_Cost.quote_no,
cl$invoices.total "Invoiced Amt incl VAT",
cl$invoices.invoice_no
FROM VW_Learners_Train_Cost
INNER JOIN cl$invoices
ON cl$invoices.project_id = VW_Learners_Train_Cost.PROJECT_ID
AND cl$invoices.client_id = VW_Learners_Train_Cost.client_id
结果 Results
预期 Expected
答案 0 :(得分:0)
我认为您的问题是您在第二个查询中加入了两次:
ON cl$invoices.project_id = VW_Learners_Train_Cost.PROJECT_ID
AND cl$invoices.client_id = VW_Learners_Train_Cost.client_id
假设两个查询都试图获得相同(良好,相似)的输出。