Question

我正在尝试解析完整的JSON结构。我已经能够获得单独的嵌套对象，但我希望它比查找每个嵌套结构简单得多。

这是我的JSON结构：

{
"request1": {
    "nest11": "solution11",
    "nest12": "solution12"
},
"request2": {
    "nest21": "solution21",
    "nest22": "solution22"
},
"request3": true,
"request3": {
    "nest31": "solution31",
    "nest32": "solution31",
    "nestnest1": {
        "nestnest11": "nestsolution11",
        "nestnest12": "nestsolution12"
    },
    "nestrequest2": {
        "nestrequest21": [{
            "nestnest21": "solution21",
            "nestnest22": "solution22"
        }]
    },
    "request4": "solution4"
}
}

当我从API获得响应时，让我们说$ serverResponse，我正在解码以获取对象

$newobj = json_decode($serverResponse);

foreach ($newobj->request1 as $key=>$value) {
  $request1 = "request1.".$key.": <b>". $value."</b><br/>";
  }

然后我将它发送回前端进行打印。问题是我该怎么做，所以我不必遍历每个对象并获得单个值。我需要打印所有键值，无论是否嵌套。感谢您的任何指示和帮助！

Answer 1

IUnitOfWork

function recursivePrinter($data){
    foreach($data as $k=>$v){
        if(is_array($v)) recursivePrinter($v);
        else echo "$k - $v";
    }
}
recursivePrinter(json_decode($response, true));

解析PHP中的解码嵌套/混合JSON

1 个答案: