Question

我有以下返回的查询：

"Code1""Code2""Code3"

我需要的是结果是这样的CSV格式：

'Code1','Code2','Code3'

如何修改代码才能完成此操作？

<?php

$conn = new mysqli("127.0.0.1", "user", "password", "table", "3306");

if(mysqli_connect_errno($conn)) {
echo "Unable to connect to database server";
}  

$result = mysqli_query($conn,"SELECT code FROM sourcecodes");
while($row = $result->fetch_assoc()) {
    $mydata = ($row['code']);
    echo json_encode($mydata);
}

$result->free();
$conn->close();
?>

Answer 1

每次迭代都应该推送到数组。构建阵列后，您可以将其转换为json并回显它。

$mydata = array();
while ($row = $result->fetch_assoc()) {
    $mydata[] = $row['code'];
}
$json = json_encode($mydata);
$string = str_replace(array('[', ']'), '', $json);
echo $string;

Answer 2

试试这个

<?php

$conn = new mysqli("127.0.0.1", "user", "password", "table", "3306");

if(mysqli_connect_errno($conn)) {
echo "Unable to connect to database server";
}  

$result = mysqli_query($conn,"SELECT code FROM sourcecodes");
while($row = $result->fetch_assoc()) {
    $mydata[] = $row['code'];

}

$result->free();
$conn->close();

 echo "'".implode("','",$mydata)."'";
?>

或者您需要json_encode？

使用PHP将mysqli查询作为逗号分隔值返回

2 个答案: