Question

使用SQL Server 2014，如何返回1或0的表，然后计算多个字段名称的相似表中匹配的1，按[Loan Identifier]进行分组。我目前有一个名为dbo.Tape的表，它是原始表，然后是dbo。[Tape Capture]用户正在更新。两个表中的[贷款标识符]相同。

谢谢你能提供帮助。

SELECT       
   [Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
FROM 
   dbo.Tape

EXCEPT

SELECT      
    [Loan Identifier], [Completion date], [Tenure], [Underwriter name]  
FROM 
    dbo.[Tape Capture]

如果[Completion date]中的dbo.Tape与[Completion date]中的dbo.[Tape Capture]匹配，那么我想返回1，否则为0。然后我想在每列中总结所有这些值。例如，

dbo。[磁带捕获] ：

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    01/01/2016       Freehold     James Mac
2                    01/01/2016       Leasehold    James Mac
3                    02/01/2016       Freehold     James Mac
4                    01/01/2016       Leasehold    James Mac
5                    03/01/2016       Freehold     James Mac

dbo.Tape ：

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    01/01/2016       Freehold     James Mac
2                    01/01/2016       Freehold     James Mac
3                    01/01/2016       Freehold     James Mac
4                    01/01/2016       Freehold     James Mac
5                    01/01/2016       Freehold     James Mac

然后我想要结果表：

[Loan Identifier], [Completion date], [Tenure], [Underwriter name] 
1                    1                  1          1
2                    1                  0          1
3                    0                  1          1
4                    1                  0          1
5                    0                  1          1

从这里，我想总结每一栏的价值。

Answer 1

SELECT T.[Loan Identifier], 
       CASE 
         WHEN TC.[Completion date] = T.[Completion date] THEN 1 
         ELSE 0 
       END AS [Completion date], 
       CASE 
         WHEN TC.[Tenure] = T.[Tenure] THEN 1 
         ELSE 0 
       END AS [Tenure], 
       CASE 
         WHEN TC.[Underwriter name] = T.[Underwriter name] THEN 1 
         ELSE 0 
       END AS [Underwriter name] 
FROM   [dbo].[Tape] AS T 
       LEFT JOIN [dbo].[Tape Capture] AS TC 
              ON T.[Loan Identifier] = TC.[Loan Identifier]

插入1或0，其中EXCEPT在比较表时返回值

1 个答案: