Question

我的应用程序适用于以下代码。即，点击一次按钮即可打开google.com。

function scan(arr, w) {

    // This function is a first attempt to solve your specific problem.
    // It just looks for the first occurence of w, the word you are looking for
    // It does not cover edge or specific cases, neither is optimized.
    // With more specifications, it can be generalized.
    // Hope it can help.

    var 
        // utils
        regWord = /\w+/g,
        wordsBefore, wordsAfter,
        matchWord,
        found = false;

    // loop through your array
    arr.forEach(function(item) {

    if (found) {
      // if we have already found the word, skip the iteration
      return false;
    }

    // clear the arrays of words before and after
    wordsBefore = []; 
    wordsAfter = [];

    // strip the words from the array item
    // every match is an iterable object containing the word, its index, and the item string
    while (match = regWord.exec(item)) {

      // get the matched word 
      matchWord = match[0].toLowerCase();

      // if we have found the word we are looking for
      if (matchWord === w.toLowerCase()) {

        // flag it
        found = true;

      } else {
        // it is not a match, but a word that could be returned in the array before or after

        if (!found) {
          // if we have not found the word yet

          // populate the array of words before
          wordsBefore.push(matchWord);

        } else {
          // otherwise, if we are here, it means that we are in a sentence containing
          // the word we are looking for, and we have already found it

          // populate the array of words after
          wordsAfter.push(matchWord);

        }

      }

    }

  });


  // return an object containing
  return {
    // the words before
    wordsBefore: wordsBefore,
    // the words after
    wordsAfter: wordsAfter 
  } 

}

现在，假设某人正在使用我的应用程序，几天后我想将网址从google.com更改为yahoo.com，我应该遵循什么方法。我对它完全无能为力。我是否应该获得域名并将其重定向更改为abc.com/test.html以重定向到google.com，然后将更改方向更改为yahoo.com或其他方法？

Answer 1

我可以给你两个想法：

在您的代码中保留一系列网址，然后随机选择一个以使用。
如果你维护一个服务器，那么你可以使用一个静态网址，你的程序将从那里接收只有url或url列表的数据并使用它。

如何在kivy中动态更改浏览器URL

1 个答案: