Question

我正在尝试匹配英尺和英寸，但我无法获得“和/或”，所以如果上半部分是正确的，它会验证：

代码:(在javascript中）

var pattern = "^(([0-9]{1,}\')?([0-9]{1,}\x22)?)+$";

function testing(input, pattern) {
        var regex = new RegExp(pattern, "g");
        console.log('Validate '+input+' against ' + pattern);
        console.log(regex.test(input));
    }

有效测试应该是：

1'
1'2"
2"
2（假设英寸）

无效应该是： *任何其他包括空的 * 1'1'

但我的正则表达式匹配无效的1'1'。

Answer 1

删除末尾的+（现在允许多个英尺/英寸的实例）并使用单独的negative lookahead assertion检查空字符串或1'2之类的非法条目。我也更改了正则表达式，因此第1组包含脚，第2组包含英寸（如果匹配）：

^(?!$|.*\'[^\x22]+$)(?:([0-9]+)\')?(?:([0-9]+)\x22?)?$

测试live on regex101.com。

<强>解释

^          # Start of string
(?!        # Assert that the following can't match here:
 $         # the end of string marker (excluding empty strings from match)
|          # or
 .*\'      # any string that contains a '
 [^\x22]+  # if anything follows that doesn't include a "
 $         # until the end of the string (excluding invalid input like 1'2)
)          # End of lookahead assertion
(?:        # Start of non-capturing group:
 ([0-9]+)  # Match an integer, capture it in group 1
 \'        # Match a ' (mandatory)
)?         # Make the entire group optional
(?:        # Start of non-capturing group:
 ([0-9]+)  # Match an integer, capture it in group 2
 \x22?     # Match a " (optional)
)?         # Make the entire group optional
$          # End of string

Answer 2

试试这个

var pattern = "^\d+(\'?(\d+\x22)?|\x22)$";

正则表达式（JavaScript）：匹配英尺和/或英寸

2 个答案: