电子邮件保存在数据库中,值为0

时间:2016-01-18 20:38:14

标签: java android database android-studio

我正在为我的应用程序执行注册登录活动,当我注册所有信息时,除了电子邮件之外,所有信息都将转到我的数据库。即使我输入了正常的电子邮件地址,我在数据库中得到一个“0”值。

我检查了我的代码和我的php文件中的所有内容,但找不到问题。

public class createAccountActivity extends AppCompatActivity implements View.OnClickListener {

EditText etUsername,etEmail, etAge, etPassword;
Button register;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.createaccount);


    etUsername = (EditText) findViewById(R.id.create_username);
    etEmail = (EditText) findViewById(R.id.create_email);
    etAge = (EditText) findViewById(R.id.create_age);
    etPassword = (EditText) findViewById(R.id.create_password);
    etConfirmPassword = (EditText) findViewById(R.id.confirm_password);




}

@Override
public void onClick (View v) {
    switch (v.getId()){
        case R.id.register:


            String username = etUsername.getText().toString();
            String email = etEmail.getText().toString();
            int age = Integer.parseInt(etAge.getText().toString());
            String password = etPassword.getText().toString();

            User user = new User(username, email, age, password);
            registerUser(user);

            break;
    }

}

private void registerUser(User user) {
    ServerRequests serverRequest = new ServerRequests(this);
    serverRequest.storeUserDataInBackground(user, new GetUserCallback() {
        @Override
        public void done(User returnedUser) {
            Intent loginIntent = new Intent(createAccountActivity.this, Login.class);
            startActivity(loginIntent);
        }
    });
}

}

在我的UserLocalStore.java中,我得到了

public void storeUserData(User user) {
    SharedPreferences.Editor userLocalDatabaseEditor = userLocalDatabase.edit();
    userLocalDatabaseEditor.putString("username", user.username);
    userLocalDatabaseEditor.putString("email", user.email);
    userLocalDatabaseEditor.putString("password", user.password);
    userLocalDatabaseEditor.putInt("age", user.age);
    userLocalDatabaseEditor.commit();
}

我的班级用户

public class User {

String username, email, password;
int age;

public User(String username,String email , int age, String password) {
    this.username = username;
    this.age = age;
    this.email = email;
    this.password = password;
}

public User(String username, String password) {
    this(username,"", -1, password);
}
}

我的ServerRequests.class

if (jObject.length() != 0){
                Log.v("happened", "2");
                String username = jObject.getString("username");
                int age = jObject.getInt("age");
                String email = jObject.getString("email");

                returnedUser = new User(username,  user.username, age, user.password);
            }

        } catch (Exception e) {
            e.printStackTrace();
        }

        return returnedUser;
    }

2 个答案:

答案 0 :(得分:0)

似乎ServerRequests.class中的returnedUser将user.username放在电子邮件应该放在的位置,因为你已将其声明为

public User(String username,String email , int age, String password)

它说

returnedUser = new User(username,  user.username, age, user.password);

在另一个档案中。

答案 1 :(得分:0)

答案很简单,在我的register.php中它写的是“siss”而不是“ssis”所以它被视为一个int。

mysqli_stmt_bind_param($statement, "siss", $username, $email, $age,  $password);

正确的一个:

mysqli_stmt_bind_param($statement, "ssis", $username, $email, $age, $password);

对不起,我应该提供它(php文件),难怪我没有得到解决方案。