我已经尝试过这个PHP代码从eml文件中提取电子邮件地址。但它在浏览器上显示我这样:
Array ( [0] => jessy87421@gmail.com
[1] => gmail.com@gmail.com
[8] => tkm.ab234@gmail.com
[16] => rjsajal99@gmail.com
[23] => mrwsamson@hotmail.com
[26] => p7896546@gmail.com
[33] => COL401-EAS320FA71AB8D0DB70A86C0BDAACA0@phx.gbl
[35] => Mrwsamson@hotmail.com [64] => stancojim@yahoo.com
[67] => 284187.29155.bm@omp1028.mail.bf1.yahoo.com [68] => 1452613452.95435.YahooMailMobile@web161005.mail.bf1.yahoo.com
[87] => prantomollick9911@gmail.com
[94] => quakenbush_87@hotmail.com
[97] => k018707707@gmail.com
[104] => BLU403-EAS1665B11DD307579691E9A1A96CA0@phx.gbl
)`
我的PHP代码是:
<?php
$emails = array();
foreach(rglob("*.eml") as $eml){
$emlContent = file_get_contents($eml);
preg_match_all('/([A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,6})/i', $emlContent, $matches, PREG_PATTERN_ORDER);
for ($i = 0; $i < count($matches[1]); $i++) {
$emails[] .= $matches[1][$i];
}
}
$emails = array_unique($emails);
print_r($emails);
function rglob($pattern='*', $flags = 0, $path=''){
$paths=glob($path.'*', GLOB_MARK|GLOB_ONLYDIR|GLOB_NOSORT);
$files=glob($path.$pattern, $flags);
foreach ($paths as $path) {
$files=array_merge($files,rglob($pattern, $flags, $path));
}
return $files;
}
?>
现在我想只将所有发件人电子邮件地址提取到Excel文件中。我在互联网上搜索过但没有得到任何解决方案。
希望有人能帮我解决问题。 提前致谢
答案 0 :(得分:1)
尝试将此标题信息添加到您的函数中,这将开始下载:
header("Content-type: application/octet-stream");
header("Content-Disposition: attachment; filename=emails.xls");
header("Pragma: no-cache");
header("Expires: 0");
foreach($emails as $email){
echo $email;
}
答案 1 :(得分:0)
您是否尝试过解析eml文件中的标题?
当文件中出现两个连续的行结束时,标题结束。
例如:
list($header, body) = explode("\n\n", file_get_contents("mail.eml"));
$headers = http_parse_headers ($header);
var_dump(headers);
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