Question

我想获取前10个结果，我传递给任何网址作为参数..我想为某些网站制作数据抓取器

在屏幕上打印结果时出现语法错误这行语法错误我不知道为什么它给我语法错误，请帮助我......

print_r（$ dse-＆gt; crawl（） - ＆gt; parse（））;

<?php               
      class CURL_CRAWLER{
      public $url;
      public $request_type;
      public $data;
      public $post_params;

  function __construct($url = '' , $request_type = 'GET')
  {
     $this->url = $url;
     $this->request_type = $request_type;
     $this->data = '';
     $this->post_params = array();
   }
/**crawl a document **/
 function crawl()
   {
    $curl = curl_init( $this->url );
    curl_setopt($curl, CURLOPT_HEADER, false);
    curl_setopt($curl, CURLOPT_TIMEOUT, 60);
    curl_setopt($curl, CURLOPT_USERAGENT, 'cURL PHP');
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
    $this->data = curl_exec($curl);
    curl_close($curl);
    return $this; //make it a chainable method
   }
/** Parse result data **/
   function parse(){
   $result = array();
   $count = 0;
   $dom = new DOMDocument;
   $dom->preserveWhiteSpace = false;
   $dom->loadHTML($this->data);
   $xpath = new DOMXPath($dom);
   $news = $xpath->query('//td[@bgcolor="#DDDDDD"]/table/tr[position()=2]/td[position()=2]');
   foreach( $news as $n){
       $result[] =   $n->nodeValue;
       $count++;
       if ($count >9)
           break; //we just need  10 results. Index starts from 0
   }
   return $result;
      }
    }
 error_reporting(0);
        $dse = new CURL_CRAWLER('http://www.dsebd.org/display_news.php');
    echo "<pre>";
    print_r( $dse-&gt;crawl()-&gt;parse() );
    echo "<pre>";

   ?>

Answer 1

您的语法错误是您应该使用显式的“大于”符号而不是HTML实体> - 服务器不需要那些，它不是可以正确呈现它的浏览器。只需改变：

print_r( $dse-&gt;crawl()-&gt;parse() );
              ^^^^        ^^^^

为：

print_r( $dse->crawl()->parse() );

得到Php卷曲错误

1 个答案: