Question

这是Ruby程序，我必须使用文件中的数据使用正则表达式提取特定字段。文件中的数据采用以下格式：

Nov 13 01:46:57 10.232.47.76 qas-adaptiveip：10-232-47-76 2015-11-13 01:46:57 +0000 [info]：qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d已取消注册adap_tdagt

我需要提取以下值 1）2015-11-13 01:46:57 +0000 2）QAS-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d

我已经编写了代码，但它无法正常工作。有人可以帮我解决这个问题。

  class Task5
  def initialize
  #   @f=File.open('C:/Users/aroraku/Desktop,boc-adap_td-agent.log-2.log',r)
  @count=0
  end

  def check_line(line)
      if(line=~/deregistered adap_tdagt$/)
           line=~ (/.*(\d{4}-\d{2}-\d{2} \d{2}:\d{2}:\d{2} +\d{4})/)
               puts "#{$1}"
      end
  end

  def file_read
     open("boc-adap_td-agent.log-2.log") { |f|
          while line=f.gets do
             check_line(line)
          end
     }
    # return @count
  end
end

Answer 1

str = "Nov 13 01:46:57 10.232.47.76 qas-adaptiveip-10-232-47-76 2015-11-13 01:46:57 +0000 [info]: qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d has been deregistered adap_tdagt"

由于您的代码存在问题，我想建议另一种方法从每行提取所需信息：

r = /
    (?:                # begin a non-capture group
      \d{4}-\d{2}-\d{2}\s\d{2}:\d{2}:\d{2}\s\+\d{4} # match date string
    )                  # end non-capture group
    |                  # or
    (?:                # begin a non-capture group
      (?<=\[info\]:\s) # match "[info:] " in a positive lookbehind
      \S+              # match >= 1 characters other than whitespace
    )                  # end non-capture group
    /x                 # extended/free-spacing regex definition mode

str.scan(r)
  #=> ["2015-11-13 01:46:57 +0000", "qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d"]

Answer 2

你必须逃避+签署日期：

line =~ /.*(\d{4}-\d{2}-\d{2} \d{2}:\d{2}:\d{2} \+\d{4}).+([a-z]{3}-[a-f0-9]{40})/
puts $1 # 2015-11-13 01:46:57 +0000
puts $2 # qas-296d1fa95fd0ac5a84ea73234c0c48d64f6ea22d

从Ruby中的Data中提取特定字段

2 个答案: