Question

我有2页..一个登录页面（login.php）和一个用户页面（useracc-test.php）..每次登录useracc-test-php时，我都可以从我的表中检索数据（用户））但我无法将新数据插入另一个名为（useradvert）的表中。我有2个表，但是我试图插入的数据是一个名为（useradvert）的表。我收到这个错误。非常感谢您的帮助.. tq。

下面是我的用户页面的脚本（useracc-test.php）：

  <?php

//useracc-test.php

/**
 * Start the session.
 */
session_start();
ini_set('display_errors', 1);
error_reporting(E_ALL);



// require 'lib/password.php';
require 'connect-test.php';


$userName= isset($_POST['username']) ? $_POST['username'] : '';




$query = "SELECT id, name, username, telno FROM users WHERE username = ?";
$stmt = $conn->prepare($query);
$stmt->bind_param('s', $userName);
$stmt->execute();
$res = $stmt->get_result();


 ?>




<html>
<head>
<style type="text/css">
#apDiv2 {
    position: absolute;
    left: 51px;
    top: 238px;
    width: 237px;
    height: 93px;
    z-index: 1;
}
#apDiv1 {
    position: absolute;
    left: 134px;
    top: 123px;
    width: 234px;
    height: 104px;
    z-index: 2;
}
#apDiv3 {
    position: absolute;
    left: 58px;
    top: 146px;
    width: 219px;
    height: 61px;
    z-index: 2;
}
#apDiv4 {
    position: absolute;
    left: 302px;
    top: 102px;
    width: 365px;
    height: 123px;
    z-index: 3;
}
</style>
<link href="SpryAssets/SpryTabbedPanels.css" rel="stylesheet" type="text/css">
<script src="SpryAssets/SpryTabbedPanels.js" type="text/javascript"></script>
</head>
<body>
Your Personal details:</p>
      <p><?php while($row = $res->fetch_array()): ?>
<p><?php echo $row['id']; ?></p>
<p><?php echo $row['name']; ?></p>
<p><?php echo $row['username']; ?></p>
<p><?php echo $row['telno']; ?>





  <?php     

  // $userid = $_POST['id'];
  $stmt=$conn->prepare("INSERT INTO useradvert (id,name2,color2,hobby2) VALUES (?,?,?,?)");
  $stmt->bind_param("isss", $id, $name2, $color2, $hobby2);
  $stmt->execute();
  if (!$stmt)
  { printf("Errormessage: %s\n", $mysqli->error);}
  else {

  echo "New records created successfully";}

$stmt->close();
$conn->close();

    ?>  





<form name="form2" method="post" action="useracc-test.php">
        <p>INSERT YOUR INTEREST:</p>
        <p>     
        </p>
          ID:
      <input name="id" type="hidden" id="id" value="<?php echo $row['id']; ?>">


  <p>Name :
          <input type="text" name="name2" id="name2">
        </p>
        <p>
          <label for="warna2"></label>
          Color :
          <input type="text" name="color2" id="color2">
        </p>
        <p>
          <label for="hobi2"></label>
          Hobby:
          <input type="text" name="hobby2" id="hobby2">
        </p>
        <p>
          <input type="submit" name="submit" id="submit" value="submit">
       </p>
        <p>&nbsp;</p>
      </form>       

               <?php endwhile; ?>

               </body>
               </html>        


--
-- Table structure for table `useradvert`
--

CREATE TABLE IF NOT EXISTS `useradvert` (
  `id` int(10) unsigned NOT NULL,
  `name2` varchar(60) COLLATE utf8_unicode_ci NOT NULL,
  `color2` varchar(60) COLLATE utf8_unicode_ci NOT NULL,
  `hobby2` varchar(60) COLLATE utf8_unicode_ci NOT NULL,
  KEY `id` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

-- --------------------------------------------------------

--
-- Table structure for table `users`
--

CREATE TABLE IF NOT EXISTS `users` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `name` varchar(60) COLLATE utf8_unicode_ci NOT NULL,
  `telno` varchar(11) COLLATE utf8_unicode_ci NOT NULL,
  `username` varchar(60) COLLATE utf8_unicode_ci NOT NULL,
  `password` varchar(60) COLLATE utf8_unicode_ci NOT NULL,
  `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  PRIMARY KEY (`id`),
  UNIQUE KEY `username` (`username`),
  KEY `id` (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=96 ;

--
-- Dumping data for table `users`
--

INSERT INTO `users` (`id`, `name`, `telno`, `username`, `password`, `date`) VALUES
(95, 'Test Name', '09999999999', 'test@test.com', '$2y$12$fqdmAQk5c8qk8Eh2TWy2n.AdNO.lFjqmi2ruSzk8tsVXcK71OcPae', '2015-12-24 05:00:13');

--
-- Constraints for dumped tables
--

--
-- Constraints for table `useradvert`
--
ALTER TABLE `useradvert`
  ADD CONSTRAINT `useradvert_ibfk_1` FOREIGN KEY (`id`) REFERENCES `users` (`id`);

Answer 1

你的问题就在这里：

$sql = sprintf ("INSERT INTO useradvert (ID, name2, color2, hobby2) VALUES (%d, '%s', '%s', '%s')",  (int)
// V- here
$result['ID'], // <- here
// ^- here
mysqli_real_escape_string($conn, $name2),
 mysqli_real_escape_string($conn, $color2),
  mysqli_real_escape_string($conn, $hobby2));

正如错误消息所示，您无法作为数组访问mysqli_result - 您必须先将每行fetch()放入一个数组中。此外，即使它是有效的语法，我也无法看到ID的值来自哪里，因为它不是查询产生结果的列之一。

你真的应该使用预备语句。除了防止SQL注入攻击之外，预准备语句还处理查询参数的所有引用和类型转换。您的第一个查询（选择）将写为

$query = "SELECT name, username, telno
            FROM users
            WHERE username = ?";
$stmt = $conn->prepare($query);
$stmt->bind_param('s', $userName);
$stmt->execute();
$res = $stmt->get_result();
$row = $res->fetch_array();

你的第二个看起来像

$userid = $_POST['ID'];
$query = "INSERT INTO useradvert
              (id, name2, color2, hobby2)
            VALUES
              (?, ?, ?, ?)";
$stmt = $conn->prepare($query);
$stmt->bind_params('isss', $userid, $name2, $color2, $hobby2);
$stmt->execute();

（请注意，在这两种情况下，我都省略了任何类型的错误处理，我更愿意将其作为练习留给读者。）

对于主键，您可以使用唯一标识该行的任何列（或列集），并且 在此期间不会更改行的生命周期 。

Answer 2

我解决了两个问题......感谢达尔文的指导......但我仍然无法将数据插入到useradvert表中。我的代码出了什么问题？

$query = "SELECT name, username, telno FROM users WHERE username = ?";
$stmt = $conn->prepare($query);
$stmt->bind_param('s', $userName);
$stmt->execute();
$res = $stmt->get_result();

 <p><?php while($row = $res->fetch_array()): ?>
   <p><?php echo $row['name']; ?></p>
<p><?php echo $row['username']; ?></p>
<p><?php echo $row['telno']; ?>
        <?php endwhile; ?>

************************

 <?php     

  $stmt=$conn->prepare("INSERT INTO useradvert (name2,color2,hobby2) VALUES (?,?,?)");
  $stmt->bind_param("sss", $name2, $color2, $hobby2);
  $stmt->execute();

  echo "New records created successfully";

$stmt->close();
$conn->close();?>

Answer 3

难怪数据没有插入..忘了if（isset（$ _ POST [＆＃39; submit＆＃39;]））.. LoL

致命错误：无法在第97行

3 个答案: